Algorithm

1. Start
2. Declare an integer variable 'number'
3. Read input into 'number' from the user
4. If (number % 2 == 0)
     4.1 Display "Number is even"
   Else
     4.2 Display "Number is odd"
5. End

Code Examples

#1 Code Example- C++ Programing Check Whether Number is Even or Odd using if else

Code - C++ Programming

#include <iostream>
using namespace std;

int main() {
  int n;

  cout << "Enter an integer: ";
  cin >> n;

  if ( n % 2 == 0)
    cout << n << " is even.";
  else
    cout << n << " is odd.";

  return 0;
}
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Output

x
–
+
cmd
Enter an integer: 23
23 is odd.

#2 Code Example- C++ Programing Check Whether Number is Even or Odd using ternary operators

Code - C++ Programming

#include <iostream>
using namespace std;

int main() {
  int n;

  cout << "Enter an integer: ";
  cin >> n;
    
  (n % 2 == 0) ? cout << n << " is even." :  cout << n << " is odd.";
    
  return 0;
}
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Output

x
–
+
cmd
Enter an integer: 23
23 is odd.
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Demonstration

C++ Programing Example to Check Whether Number is Even or Odd-DevsEnv