Algorithm

  1. Input:

    • i. Prompt the user to enter the coefficients a, b, and c of a quadratic equation.

  2. Calculate Discriminant:

    • i. Calculate the discriminant using the formula discriminant = b*b - 4*a*c.

  3. Check Discriminant Value:

    • 1. If discriminant > 0, there are two real roots. Calculate them using the quadratic formula:
      • ii. root1 = (-b + sqrt(discriminant)) / (2*a)
      • iii. root2 = (-b - sqrt(discriminant)) / (2*a)
    • If discriminant == 0, there is one real root (a repeated root). Calculate it using:
      • i. root1 = root2 = -b / (2*a)
    • If discriminant < 0, roots are imaginary, and the program cannot compute them.

  4. Output Roots:

    • 1. Print the roots of the equation based on the conditions met:
      • i. If two real roots: printf("The roots of the equation are: %f and %f", root1, root2);
      • ii. If one real root: printf("The roots of the equation are equal and have the value: %f and %f", root1, root2);
      • iii. If imaginary roots: printf("The roots of the equation are imaginary and hence we cannot compute them");

 

Code Examples

#1 Code Example-C Programing Implementation Code

Code - C Programming

# include<stdio.h>
# include<conio.h>
# include<math.h>

int main (){
    
   float a,b,c;
   printf (“Enter the values of coefficient: a, b, and c”);
   scanf (“ %f %f %f”, &a, &b, &c);
    
   float discriminant;
   discriminant= b*b – 4*a*c;
    
   float root1, root2;
    
   if (discriminant>0){
      root1 = -b+sqrt (discriminant) / (2*a);
      root2 = -b-sqrt (discriminant) / (2*a);
      printf (“The roots of the equation are = %f %f”, r1, r2);
   }
   else if (discriminant==0){
      root1 = -b/(2*a);
      root2 = -b/(2*a);
      printf (“The roots of the equation are equal having the value =%f %f”, r1, r2);
   }
   else
      printf(“The roots of the equation are imaginary and hence we can not compute them”);
}
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Output

x
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cmd
The roots of the equation are = -1 -3

#2 Code Example-C Programing Find the values of a, b, and c in a quadratic equation

Code - C Programming

#include<stdio.h>
#include<math.h>
 
int main(){
  
  float a,b,c;
  float d,root1,root2;  
 
  printf("Enter the quadratic equation in the format ax^2+bx+c: ");
  scanf("%fx^2%fx%f",&a,&b,&c);
   
  float discriminant;
  discriminant = b * b - 4 * a * c;
  
  if(discriminant < 0){
    printf("Roots are imaginary number.\n");
    continue;
  }
 
   float root1, root2;
    
   root1 = ( -b + sqrt(discriminant)) / (2* a);
   root2 = ( -b - sqrt(discriminant)) / (2* a);
    
   printf("Roots of quadratic equation are: %f and %f",root1,root2>;

}
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Output

x
–
+
cmd
Enter quadratic equation in the format ax^2+bx+c: 2x^2+4x+(-1)
The roots of the quadratic equation are: 0 and -2
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Demonstration

C Programing Example to Find the Roots of a Quadratic Equation-DevsEnv

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