## Algorithm

START Algorithm

1. Step 1 → Take an integer variable of `year `
2. Step 2 → Assign a value to that variable
3. Step 3 → Check if the year is `divisible by 4 but not 100, print "Leap Year"`
4. Step 4 → Check if the year is `divisible by 400, print "Leap Year"`
5. Step 5 → Else, print "Not Leap Year"

STOP Algorithm

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````#include <stdio.h>

int main() {
int year;
printf("Please Enter year to check leap year: ");
scanf("%d", &year); // Take input for year variable

if ( ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0) ) { // If Divisible by 4 and not 100 or Divisible by 400
printf("%d is a Leap Year", year);
} else {
printf("%d is not a Leap Year", year);
}

return 0;
}
``````
Copy The Code &

Input

cmd
2000

Output

cmd
Please Enter year to check leap year: 2000
2000 is a Leap Year

### #2 Code Example with C Programming

```Code - C Programming```

``````#include <stdio.h>
int main() {
int year;
printf("Enter a year: ");
scanf("%d", &year);

if (year % 400 == 0) { //If year is divisible by 400, Leap year
printf("%d is a Leap year.", year);
} else if (year % 100 == 0) {    // Not Leap year if divisible by 100 but not divisible by 400
printf("%d is not a Leap year.", year);
} else if (year % 4 == 0) { // leap year if not divisible by 100 but divisible by 4
printf("%d is a Leap year.", year);
} else {
printf("%d is not a Leap year.", year);
}

return 0;
}``````
Copy The Code &

Input

cmd
1999

Output

cmd
Enter a year:1999
1999 is not a Leap year

### #3 Get all leap years between a range

```Code - C Programming```

``````#include<stdio.h>

int main() {
int startYear, endYear, year;

printf ("Enter a Start Year to check leap years: ");
scanf ("%d", &startYear);

printf ("Enter an End year to check leap years: ");
scanf ("%d", &endYear);

printf ("Leap Years between %d to %d are: \n", startYear, endYear);

for (year = startYear; year  < = endYear; year++)
{
if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))
{
printf("%d \n", year);
}
}

return 0;
}``````
Copy The Code &

Input

cmd
2000
2023

Output

cmd
Enter a Start Year to check leap years: 2000
Enter an End year to check leap years: 2023
Leap Years between 2000 to 2023 are:
2000
2004
2008
2012
2016
2020
2. Then year will be leap year only if it is `divisible by 4, but not 100`
3. Or, if it is `divisible by 400, then leap year`