Algorithm
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Input the year to be checked.
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If the year is evenly divisible by 4, go to the next step. If not, the year is not a leap year.
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If the year is divisible by 4, but not by 100, go to the next step. If the year is divisible by both 4 and 100, go to step 4.
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If the year is divisible by 100 but not divisible by 400, then the year is not a leap year. If the year is divisible by both 100 and 400, go to the next step.
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If the year is divisible by 400, then it is a leap year. Otherwise, it is not.
Code Examples
#1 Code Example- Java Program to Check a Leap Year
Code -
Java Programming
public class Main {
public static void main(String[] args) {
// year to be checked
int year = 1900;
boolean leap = false;
// if the year is divided by 4
if (year % 4 == 0) {
// if the year is century
if (year % 100 == 0) {
// if year is divided by 400
// then it is a leap year
if (year % 400 == 0)
leap = true;
else
leap = false;
}
// if the year is not century
else
leap = true;
}
else
leap = false;
if (leap)
System.out.println(year + " is a leap year.");
else
System.out.println(year + " is not a leap year.");
}
}Output
1900 is not a leap year.
Demonstration
Java Programing to Check Leap Year-DevsEnv