## Algorithm

1. Input the year to be checked.

2. If the year is evenly divisible by 4, go to the next step. If not, the year is not a leap year.

3. If the year is divisible by 4, but not by 100, go to the next step. If the year is divisible by both 4 and 100, go to step 4.

4. If the year is divisible by 100 but not divisible by 400, then the year is not a leap year. If the year is divisible by both 100 and 400, go to the next step.

5. If the year is divisible by 400, then it is a leap year. Otherwise, it is not.

## Code Examples

### #1 Code Example- Java Program to Check a Leap Year

```Code - Java Programming```

``````public class Main {

public static void main(String[] args) {

// year to be checked
int year = 1900;
boolean leap = false;

// if the year is divided by 4
if (year % 4 == 0) {

// if the year is century
if (year % 100 == 0) {

// if year is divided by 400
// then it is a leap year
if (year % 400 == 0)
leap = true;
else
leap = false;
}

// if the year is not century
else
leap = true;
}

else
leap = false;

if (leap)
System.out.println(year + " is a leap year.");
else
System.out.println(year + " is not a leap year.");
}
}``````
Copy The Code &

Output

cmd
1900 is not a leap year.