Algorithm
problem Link : https://www.codechef.com/problems/CHEFONDATE
Problem
Chef and his girlfriend go on a date. Chef took dollars with him, and was quite sure that this would be enough to pay the bill. At the end, the waiter brought a bill of dollars. Print "YES"
if Chef has enough money to pay the bill, or "NO"
if he has to borrow from his girlfriend and leave a bad impression on her.
Input Format
- The first line of input will contain a single integer , denoting the number of test cases.
- Each test case consists of a single line of input, containing two space-separated integers and .
Output Format
For each test case, output on a new line "YES"
if Chef has enough money to pay the bill and "NO"
otherwise.
You may print each character of the string in either uppercase or lowercase (for example, the strings "yEs"
, "yes"
, "Yes"
and "YES"
will all be treated as identical).
Constraints
Sample 1:
4 1 1 1 2 2 1 50 100
YES NO YES NO
Explanation:
Test case : Since the money Chef has is equal to the bill, he will be able to pay the bill.
Test case : Since the money Chef has is less than the bill, he will have to borrow from his girlfriend and leave a bad impression on her.
Test case : Since the money Chef has is greater than the bill, he will be able to pay the bill.
Test case : Since the money Chef has is less than the bill, he will have to borrow from his girlfriend and leave a bad impression on her.
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include<stdio.h> int main() { int t,x,y; scanf("%d",&t); while(t--) { scanf("%d %d",&x,&y); if(x>=y) printf("YES\n"); else printf("NO\n"); } }Copy The Code & Try With Live Editor
Input
1 1
1 2
2 1
50 100
Output
NO
YES
NO
Demonstration
CodeChef solution CHEFONDATE - Chef On Date CodeChef solution in C,C++