## Problem

Chef has an exam which will start exactly  minutes from now. However, instead of preparing for his exam, Chef started watching Season-1 of Superchef. Season-1 has  episodes, and the duration of each episode is  minutes.

Will Chef be able to finish watching Season-1 strictly before the exam starts?

### Input Format

• The first line contains an integer  denoting the number of test cases.  test cases then follow.
• The first and only line of each test case contains 3 space separated integers  and .

### Output Format

For each test case, output on one line YES if it is possible to finish Season-1 strictly before the exam starts, or NO if it is not possible to do so.

Output is case insensitive, which means that "yes", "Yes", "YEs", "no", "nO" - all such strings will be acceptable.

• 1≤�≤104
• 1≤�≤109
• 1≤�,�≤104

### Sample 1:

Input

Output

3
10 1 10
25 2 10
15 2 10
NO
YES
NO

### Explanation:

Test Case 1: The duration of the only episode is 10 minutes, and the exam starts exactly after 10 minutes. So, Chef will not be able to finish watching Season-1 strictly before the exam starts.

Test Case 2: There are two episodes in Season-1, each of duration 10 minutes. Therefore, Chef will require 10+10=20 minutes to finish watching Season-1. As the exam starts after 25 minutes, Chef will be able to finish watching Season-1 strictly before the exam starts.

Test Case 3: There are two episodes in Season-1, each of duration 10 minutes. Therefore, Chef will require 10+10=20 minutes to finish watchin Season-1. As the exam starts after 15 minutes, Chef will not be able to finish watching Season-1 strictly before the exam starts.

## Code Examples

### #1 Code Example with C Programming

Code - C Programming

  #include<stdio.h>
int main()
{
int t,m,n,k;
scanf("%d",&t);
while(t--)
{
scanf("%d %d %d",&m,&n,&k);
if(m>n*k) printf("Yes\n");
else printf("No\n");
}
}
Copy The Code &

Input

cmd
3
10 1 10
25 2 1
15 2 10

Output

cmd
NO
YES
NO