Algorithm


Problem link- https://www.spoj.com/problems/NSTEPS/

NSTEPS - Number Steps

 

Starting from point (0,0) on a plane, we have written all non-negative integers 0, 1, 2, ... as shown in the figure. For example, 1, 2, and 3 has been written at points (1,1), (2,0), and (3, 1) respectively and this pattern has continued.

 

Illustration

 

You are to write a program that reads the coordinates of a point (x, y), and writes the number (if any) that has been written at that point. (x, y) coordinates in the input are in the range 0...10000.

Input

The first line of the input is N, the number of test cases for this problem. In each of the N following lines, there is x, and y representing the coordinates (x, y) of a point.

Output

For each point in the input, write the number written at that point or write No Number if there is none.

Example

Input:
3
4 2
6 6
3 4

Output:
6
12
No Number

 

Code Examples

#1 Code Example with C++ Programming

Code - C++ Programming

#include <iostream>

using namespace std;

main()
{
	long long t;
	cin>>t;
	while(t--)
	{
		int x,y;
		cin>>x>>y;
		if(x==y)
		{
			if(x%2==0&&y%2==0)
			{
				cout<<x+y<<endl;
			}
			else
			{
				cout<<x+y-1<<endl;
			}
		}
		else if(x-y==2)
		{
			if(x%2==0&&y%2==0)
			{
				cout<<x+y<<endl;
			}
			else
			{
				cout<<x+y-1<<endl;
			}
		}
		else
		{
			cout<<"No Number"<<endl;
		}
	}
}
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Input

x
+
cmd
3
4 2
6 6
3 4

Output

x
+
cmd
6
12
No Number

#2 Code Example with Java Programming

Code - Java Programming

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
public class NSTEPS {
	
	public static void main(String[] args) throws Exception
	{
		BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
		PrintWriter out = new PrintWriter(System.out);
		int numTestCases = Integer.parseInt(reader.readLine());
		for(int i = 0; i < numTestCases; i++)
		{
			String[] data = reader.readLine().split(" ");
			int x = Integer.parseInt(data[0]);
			int y = Integer.parseInt(data[1]);
			
			if(x == y || (x-y==2))
			{
				if(x % 2 == 0)
				{
					out.println(x+y);
					
				}
				else
				{
					out.println(x+y-1);
				}
			}
			else
			{
				out.println("No Number");
			}
			out.flush();
		}
	}

}
Copy The Code & Try With Live Editor

Input

x
+
cmd
3
4 2
6 6
3 4

Output

x
+
cmd
6
12
No Number
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Demonstration


SPOJ Solution-NSTEPS  Number Steps-Solution in C, C++, Java, Python ,SPOJ Solution,NSTEPS  Number Steps

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