## Algorithm

Problem Name: Python - Any or All

In this HackerRank Functions in PYTHON problem solution,

### any()

This expression returns `True` if any element of the iterable is true.
If the iterable is empty, it will return `False`.

Code

``````>>> any([1>0,1==0,1<0])
True
>>> any([1<0,2<1,3<2])
False
``````

### all()

This expression returns `True` if all of the elements of the iterable are true. If the iterable is empty, it will return `True`.

Code

``````>>> all(['a'<'b','b'<'c'])
True
>>> all(['a'<'b','c'<'b'])
False
``````

You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.

Input Format

The first line contains an integer N.N is the total number of integers in the list.
The second line contains the space separated list of N integers.

Constraints

0 < N < 100

Output Format

Print `True` if all the conditions of the problem statement are satisfied. Otherwise, print `False`.

Sample Input

``````5
12 9 61 5 14
``````

Sample Output

True

Explanation

Condition 1: All the integers in the list are positive.
Condition 2: 5 is a palindromic integer.

Hence, the output is `True`.

Can you solve this challenge in `3 lines of code or less`?
There is `no penalty` for solutions that are correct but have more than 3 lines.

## Code Examples

### #1 Code Example with Python Programming

```Code - Python Programming```

``````
N = int(input())
numbers = list(map(int, input().split()))
print(all([x > 0 for x in numbers]) and any([str(x) == str(x)[::-1] for x in numbers]))
# My best attempt at an under 3-line solution.
``````
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