Algorithm
Problem Name:
In this HackerRank Functions in C programming problem solution,You are given an array of integers, marks,, denoting the marks scored by students in a class.
- The alternating elements marks0,marks2,marks4 and so on denote the marks of boys.
- Similarly, marks1, marks3, marks0 and so on denote the marks of girls.
The array name, marks, works as a pointer which stores the base address of that array. In other words, marks contains the address where marks0 is stored in the memory.
For example, let marks = |3, 2, 5|and marks stores 0x7fff9575c05f. Then, 0x7fff9575c05f is the memory address of marks0
Function Description
Complete the function, marks_summation in the editor below.
marks_summation has the following parameters:
- int marks[number_of_students]: the marks for each student
- int number_of_students: the size of marks[]
- char gender: either 'g' or 'b'
Returns
- int: the sum of marks for boys if gender = b, or of marks of girls if gender = g
Input Format
- The first line contains number_of_students, denoting the number of students in the class, hence the number of elements in marks.
- Each of the number_of_students subsequent lines contains marksi.
- The next line contains gender.
Constraints
- 1 <= number_of_students <= 10***3
- 1 <= marksi <= 10***3 (where 0 <= i <= number_of_students)
- gender = g or b
Sample Input 0
3
3
2
5
b
Sample Output 0
8
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
//Complete the following function.
int marks_summation(int* marks, int number_of_students, char gender)
{
int sum = 0;
if(gender == 'b'){
for(int i = 0; i < number_of_students; i += 2)
sum += marks[i];
}
else{
for(int i = 1; i < number_of_students; i += 2)
sum += marks[i];
}
return sum;
}
int main()
{
int number_of_students;
char gender;
int sum;
scanf("%d", &number_of_students);
int *marks = (int *) malloc(number_of_students * sizeof (int));
for (int student = 0; student < number_of_students; student++) {
scanf("%d", (marks + student));
}
scanf(" %c", &gender);
sum = marks_summation(marks, number_of_students, gender);
printf("%d", sum);
free(marks>;
return 0;
}
Input
3
3
2
5
b
Output
8