Algorithm


Problem Name: Basic Data Types

Problem Link: https://www.hackerrank.com/challenges/c-tutorial-basic-data-types/problem?isFullScreen=true

In this HackerRank Functions in C++ programming problem solution,

Some C++ data types, their format specifiers, and their most common bit widths are as follows:

  • Int ("%d"): 32 Bit integer
  • Long ("%ld"): 64 bit integer
  • Char ("%c"): Character type
  • Float ("%f"): 32 bit real value
  • Double ("%lf"): 64 bit real value

Reading
To read a data type, use the following syntax:

scanf("`format_specifier`", &val)

For example, to read a character followed by a double:

char ch;
double d;
scanf("%c %lf", &ch, &d);

For the moment, we can ignore the spacing between format specifiers.


Printing
To print a data type, use the following syntax:

printf("`format_specifier`", val)

For example, to print a character followed by a double:

char ch = 'd';
double d = 234.432;
printf("%c %lf", ch, d);

Note: You can also use cin and cout instead of scanf and printf; however, if you are taking a million numbers as input and printing a million lines, it is faster to use scanf and printf.

Input Format

Input consists of the following space-separated values: int, long, char, float, and double, respectively.

Output Format

Print each element on a new line in the same order it was received as input. Note that the floating point value should be correct up to 3 decimal places and the double to 9 decimal places.

Sample Input

3 12345678912345 a 334.23 14049.30493

Sample Output

3
12345678912345
a
334.230
14049.304930000

 

Code Examples

#1 Code Example with C++ Programming

Code - C++ Programming


#include <iostream>
#include <iomanip>
using namespace std;

int main(void)
{
    int a;
    long b;
    long long int c;
    char d;
    float e;
    double f;

    cin >> a >> b >> c >> d >> e >> f;

    cout << a << endl;
    cout << b << endl;
    cout << c << endl;
    cout << d << endl;
    cout << fixed << setprecision(2) << e << endl;
    cout << fixed << setprecision(5) << f << endl;

    return 0;
}
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Input

x
+
cmd
3 12345678912345 a 334.23 14049.30493

Output

x
+
cmd
3 12345678912345 a 334.230 14049.304930000
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Demonstration


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