Algorithm

Problem Name: Python - Validating and Parsing Email Addresses

Problem Link: https://www.hackerrank.com/challenges/validating-named-email-addresses/problem?isFullScreen=true

In this HackerRank Functions in PYTHON problem solution,

A valid email address meets the following criteria:

 

  • It's composed of a username, domain name, and extension assembled in this format: username@domain.extension
  • The username starts with an English alphabetical character, and any subsequent characters consist of one or more of the following: alphanumeric characters, -,., and _.
  • The domain and extension contain only English alphabetical characters.
  • The extension is 1,2 or 3 characters in length.

Given n pairs of names and email addresses as input, print each name and email address pair having a valid email address on a new line.

Hint: Try using Email.utils() to complete this challenge. For example, this code:

 

import email.utils
print email.utils.parseaddr('DOSHI <DOSHI@hackerrank.com>')
print email.utils.formataddr(('DOSHI', 'DOSHI@hackerrank.com'))

 

produces this output:

 

('DOSHI', 'DOSHI@hackerrank.com')
DOSHI <DOSHI@hackerrank.com>

Input Format

The first line contains a single integer , n , denoting the number of email address.
Each line i of the n subsequent lines contains a name and an email address as two space-separated values following this format:

name <user@email.com>

Constraints

  • 0 < n < 100

Output Format

Print the space-separated name and email address pairs containing valid email addresses only. Each pair must be printed on a new line in the following format:

name <user@email.com>

You must print each valid email address in the same order as it was received as input.

Sample Input

2  
DEXTER <dexter@hotmail.com>
VIRUS <virus!@variable.:p>

Sample Output

DEXTER <dexter@hotmail.com>

Explanation

dexter@hotmail.com is a valid email address, so we print the name and email address pair received as input on a new line.
virus!@variable.:p is not a valid email address because the username contains an exclamation point (!) and the extension contains a colon (:). As this email is not valid, we print nothing.

 

 

 

 

Code Examples

#1 Code Example with Python Programming

Code - Python Programming


import re
import email.utils

for num in range(int(input())):
    unemail = input()
    email = unemail.split(" ")
    pattern = re.compile(r"^<([a-zA-Z0-9]+[-_.]*)*[a-zA-Z0-9]+@[a-z]+\.[a-z]{1,3}>$")
    result = pattern.match(email[1])
    
    if result:
        print (''.join(unemail))
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Demonstration

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