## Algorithm

Problem Name: Data Structures - Jaggu Playing with Balloons

In this HackerRank in Data Structures - Jaggu Playing with Balloons solutions,

Jaggu is a little kid and he likes playing with water balloons. He took 1 million ( 106 ) empty buckets and he filled the bucket with water balloons under the instruction of his sister Ishika.
His sister gives him two types of commands:

`R pos1 pos2` which implies that jaggu needs to tell her what is the total number of water balloons in the bucket from pos1 to pos2 (both included).

`U pos M plus` which implies that he has to work like the function

Update(pos,M,plus)

``````void Update(int pos,int M,int plus)
{
int N=1000000;  //1 million
for (int i=1;i<=50;i++)
{
int back = pos
for(int j=1;j<=1000;j++)
{
add M water ballons at bucket pos
int s,in=__builtin_popcount(pos);
for(int k=0;;k++)
{
s=pos+pow(2,k)
if( __builtin_popcount(s) <= in )
{
in = __builtin_popcount(s)
pos = s;
if(pos>N)       break;
add M water ballons at bucket pos
}
}
pos = pos - N
}
pos = back+plus;
if(pos>N) pos-=N;
}
}
``````

Jaggu is too lazy to put the water ballons in the bucket. Afraid that he might be caught for not doing what his sister told him to do so, he asks your help to provide correct answers for each of his sister's query. .

Input Format

First line contains Q, number of queries to follow.

Next Q line follows , which can be either an Update Query or Report Query.Each Update Query is followed by atleast 1 report query.

Output Format

For each report query , output the answer in a separate line.

Constraints

1 ≤ Q ≤ 2 * 105

1 ≤ pos1,pos2,pos ≤ 106

pos1 ≤ pos2

1 ≤ M ≤ 10

1 ≤ plus ≤ 999999

Sample Input

``````2
U 692778 7 291188
R 636916 747794
``````

Sample Output

``````378
``````

Explanation

Note

1. Input is randomly generated.

2. __builtin_popcount(x) gives the number of set bits in binary representation of x.

3. pow(2,k) denotes 2 raised to k , i.e. exponentiation of 2.

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````
#include <stdio.h>

int arr[]={1,983041,999425,999937,1000001};
int ar1[]={48576,15808,448,64};
long long int ar2[1000001];

long long int ans(int a)
{
long long int sum=0;
while(a)
{
sum = sum + ar2[a];
a-=(a&(-a));
}
return sum;
}

void query(int a,long long int b)
{
long long int c=b;
while(a < =1000000)
{
ar2[a]+=b;
b+=c;
a+=(a&(-a));
}
}

int main()
{
int i,N=1000000,Q,pos1,pos2,plus,j,temp;
char qry;
scanf("%d",&Q);

for(i=0;i < Q;i++){
scanf(" %c",&qry);
scanf("%d %d",&pos1,&pos2);
if(qry =='U'){
temp=0;
int counter[4]={0};
scanf("%d",&plus);

for(j=1;j<=50;j++)
{
query(pos1,pos2>;
if(pos1>=arr[temp] && pos1<arr[temp+1])
counter[temp]++;
else
{
while(1)
{
temp++;
if(temp==4>
temp=0;
if(pos1>=arr[temp] && pos1<arr[temp+1]>
{
counter[temp]++;
break;
}
}
}
pos1=pos1+plus;
if(pos1>N)
pos1=pos1-N;
}

for(j=0;j<4;j++){
if(counter[j]!=0)
query(ar1[j],pos2*(counter[j]));
}

query(ar1[0],(long long int)pos2*49900);
}
else
printf("%lld\n",ans(pos2)-ans(pos1-1)>;
}
return 0;
}
``````
Copy The Code &

### #3 Code Example with Java Programming

```Code - Java Programming```

``````
import java.util.*;
import java.io.*;

public class JagguWaterBall {
static long[] buckets = null;

static void go() {
int q = in.nextInt();

buckets = new long[1000002];
while (q-- > 0) {
String command = in.nextString();
if (command.charAt(0) == 'U') {
int p = in.nextInt();
int m = in.nextInt();
int plus = in.nextInt();
update(p, m, plus);
} else {
int p1 = in.nextInt();
int p2 = in.nextInt();
out.println(getBetween(p1-1, p2));
}
}
}

static void update(int pos, int m, int plus) {
int N = 1000000;  //1 million
for (int i = 1; i  < = 50; i++) {
//System.out.println("i= " + i);
int back = pos;
//System.out.println("start pos = " + pos);
for (int j = 1; j  < = 1000; j++) {
//System.out.println("pos1 = " + pos);
//buckets[pos] += m;
int s, in = getBITs(pos);
for (int k = 0; ; k++) {
//System.out.println("k = " + k);
s = pos + (1<<k);
if (getBITs(s)  < = in) {
in = getBITs(s);
pos = s;
if (pos > N) {
//System.out.println("pos = " + pos);
break;
}
//System.out.println("pos2 = " + pos);
//buckets[pos] += m;
}
}
//System.out.println(" j = " + j + ": " + pos);
pos = pos - N;
if (pos == 48576 && j  <  1000) {
long val = (1000 - j) * m;
break;
}
}
pos = back + plus;
//System.out.println("pos3 = " + pos);
if (pos > N)
pos -= N;
}
}

static long getBetween(int p1, int p2) {
long ret = 0;
while(p1 != p2) {
if (p2 > p1) {
ret += buckets[p2];
p2 -= (p2 & -p2);
} else {
ret -= buckets[p1];
p1 -= (p1 & -p1);
}
}
return ret;
}

long sum = 0;
while(idx > 0) {
sum += buckets[idx];
idx -= (idx & -idx);
}
return sum;
}

static void add(int idx, long x) {
while(idx  < = 1000000) {
buckets[idx] += x;
idx += (idx & -idx);
}
}

static int getBITs(long x) {
int ret = 0;
while (x > 0) {
ret++;
x &= x - 1;
}
return ret;
}

static PrintWriter out;

public static void main(String[] args) {
out = new PrintWriter(System.out);

go();

out.close();
}

private InputStream stream;
private byte[] buf = new byte[1024];
private int curChar;
private int numChars;

this.stream = stream;
}

if (numChars == -1)
throw new InputMismatchException();
if (curChar >= numChars) {
curChar = 0;
try {
} catch (IOException e) {
throw new InputMismatchException();
}
if (numChars  < = 0)
return -1;
}
return buf[curChar++];
}

public int nextInt() {
return (int) nextLong();
}

public long nextLong() {
while (isSpaceChar(c))
int sgn = 1;
if (c == '-') {
sgn = -1;
}
long res = 0;
do {
if (c  <  '0' || c > '9')
throw new InputMismatchException();
res *= 10;
res += c - '0';
} while (!isSpaceChar(c));
return res * sgn;
}

public String nextString() {
while (isSpaceChar(c))
StringBuilder sb = new StringBuilder(1024);
do {
sb.append((char) c);
} while (!isSpaceChar(c));
return sb.toString();
}

public static boolean isSpaceChar(int c) {
switch (c) {
case -1:
case ' ':
case '\n':
case '\r':
case '\t':
return true;
default:
return false;
}
}
}
}
``````
Copy The Code &