Algorithm


Problem Name: 30 days of code - Day 5: Loops

Problem Link: https://www.hackerrank.com/challenges/30-loops/problem?isFullScreen=true

In this HackerRank in 30 Days of Code - Day 5: Loops problem solution,

Objective
In this challenge, we will use loops to do some math. Check out the Tutorial tab to learn more.

Task
Given an integer, n, print its first 10 multiples. Each multiple n * i (where 1 <= i <= 10) should be printed on a new line in the form: n x i = result.

Example

n = 3

The printout should look like this:

 

3 x 1 = 3
3 x 2 = 6
3 x 3 = 9
3 x 4 = 12
3 x 5 = 15
3 x 6 = 18
3 x 7 = 21
3 x 8 = 24
3 x 9 = 27
3 x 10 = 30

 

Input Format

A single integer, n.

Constraints

2 <= n <= 20

Output Format

Print 10 lines of output; each line i (where 1 <= i <= 10) contains the result of n * i the form:
n x i = result.

Sample Input

2

Sample Output

2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20

 

 

 

 

 

Code Examples

#1 Code Example with C Programming

Code - C Programming


#include <stdio.h>

int  main()
{
    int n,i;
    scanf("%d",&n);
    for(i = 1; i  < = 0; i++)
    {
        printf("%d x %d = %d\n",n,i,n*i);
    }
        return 0;
}
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#2 Code Example with C++ Programming

Code - C++ Programming


#include <iostream>

using namespace std;

int main() {
    int N;
    cin >> N;

    for (int i = 1; i  <  11; i++) {
        printf("%i x %i = %i\n", N, i, N * i);
    }

    return 0;
}
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#3 Code Example with C# Programming

Code - C# Programming


using System;

class Solution
{
    static void Main(String[] args)
    {
        var N = int.Parse(Console.ReadLine());

        for (int i = 1; i  <  11; i++)
        {
            Console.WriteLine($"{N} x {i} = {N * i}");
        }
    }
}
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#4 Code Example with Golang Programming

Code - Golang Programming


package main

import "fmt"

func main() {
	var n int
	fmt.Scan(&n)
	for i := 1; i  < = 10; i++ {
		fmt.Printf("%d x %d = %d\n", n, i, i*n)
	}
}
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#5 Code Example with Java Programming

Code - Java Programming


import java.util.Scanner;

public class Solution {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int N = in.nextInt();
        in.close();

        for (int i = 1; i  <  11; i++) {
            System.out.println(N + " x " + i + " = " + N * i);
        }
    }
}
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#6 Code Example with Javascript Programming

Code - Javascript Programming

start coding
process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
    input_stdin += data;
});

process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("\n");
    main();    
});

function readLine() {
    return input_stdin_array[input_currentline++];
}

/////////////// ignore above this line ////////////////////

function main() {
    var N = parseInt(readLine());
    
    for (var x = 1; x  <  11; x++)
        {
            var result = N*x;
            console.log(N.toString() + " x " + x + " = " + result.toString());
        }

}
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#7 Code Example with Python Programming

Code - Python Programming


N = int(input())

for i in range(1, 11):
    print(str(N) + " x " + str(i) + " = " + str(N * i))
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Demonstration


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