## Algorithm

Problem Name: Virtual Functions

In this HackerRank Functions in C++ programming problem solution,

This problem is to get you familiar with virtual functions. Create three classes Person, Professor and Student. The class Person should have data members name and age. The classes Professor and Student should inherit from the class Person.

The class Professor should have two integer members: publications and cur_id. There will be two member functions: getdata and putdata. The function getdata should get the input from the user: the name, age and publications of the professor. The function putdata should print the name, age, publications and the cur_id of the professor.

The class Student should have two data members: marks, which is an array of size 6 and cur_id. It has two member functions: getdata and putdata. The function getdata should get the input from the user: the name, age, and the marks of the student in 6 ubjects. The function putdata should print the name, age, sum of the marks and the cur_id of the student.

For each object being created of the Professor or the Student class, sequential id's should be assigned to them starting from 1.

Solve this problem using virtual functions, constructors and static variables. You can create more data members if you want.

Note: Expand the main function to look at how the input is being handled.

Input Format

The first line of input contains the number of objects that are being created. If the first line of input for each object is 1 , it means that the object being created is of the Professor class, you will have to input the name, age and publications of the professor.

If the first line of input for each object is 2, it means that the object is of the Student class, you will have to input the name, age and the marks of the student in 6subjects.

Constraints

1 <= lenname <= 100 , wherelenname <= 100 is the length of the name.

1 <= age <= 80

1 <= 6publication <= 1000

0 <= marks <= 100, where marks is the marks of the student in each subject.

Output Format

There are two types of output depending on the object.

If the object is of type Professor, print the space separated name, age, publications and id on a new line.

If the object is of the Student class, print the space separated name, age, the sum of the marks in 6 subjects and id on a new line.

Sample Input

``````4
1
Walter 56 99
2
Jesse 18 50 48 97 76 34 98
2
Pinkman 22 10 12 0 18 45 50
1
White 58 87
``````

Sample Output

``````Walter 56 99 1
Jesse 18 403 1
Pinkman 22 135 2
White 58 87 2
``````

## Code Examples

### #1 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include <iostream>
#include <string>

using namespace std;

static int StudentId = 0;
static int ProfessorId = 0;

class Person
{
public:
string name;
int age;

virtual void getdata() {
cin >> name;
cin >> age;
}
virtual void putdata() {
cout << name << " " << age << " ";
}
};

class Student : public Person
{
public:
int marks[6];
int id;

Student() {
StudentId ++;
}

void getdata() {
Person::getdata();
for (int i = 0; i  <  6; ++i) {
cin >> marks[i];
}
id = StudentId;
}

void putdata() {
Person::putdata();
cout << this->sum() << " " << id << endl;
}

int sum() {
int sum = 0;

for (int i = 0; i  <  6; ++i) {
sum += marks[i];
}

return sum;
}
};

class Professor : public Person
{
public:
int publications;
int id;

Professor() {
ProfessorId ++;
}

void getdata() {
Person::getdata();
cin >> publications;
this->id = ProfessorId;
}

void putdata() {
Person::putdata();
cout << publications << " " << id << endl;
}
};

int main(){

int n, val;
cin>>n; //The number of objects that is going to be created.
Person *per[n];

for(int i = 0;i  <  n;i++){
cin>>val;

if(val == 1){
// If val is 1 current object is of type Professor
per[i] = new Professor;
}
else per[i] = new Student; // Else the current object is of type Student

per[i]->getdata(); // Get the data from the user.
}

for(int i=0;i<n;i++>
per[i]->putdata(); // Print the required output for each object.

return 0;

}
``````
Copy The Code &

Input

cmd
4 1 Walter 56 99 2 Jesse 18 50 48 97 76 34 98 2 Pinkman 22 10 12 0 18 45 50 1 White 58 87

Output

cmd
Walter 56 99 1 Jesse 18 403 1 Pinkman 22 135 2 White 58 87 2