Algorithm


 Problem Name: Pointers in C

Problem Link: https://www.hackerrank.com/challenges/pointer-in-c/problem?isFullScreen=true

In this HackerRank Functions in C programming problem solution,In this challenge, you will learn to implement the basic functionalities of pointers in C. A pointer in C is a way to share a memory address among different contexts (primarily functions). They are primarily used whenever a function needs to modify the content of a variable that it does not own.

In order to access the memory address of a variable,val ,prepend it with & sign. For example, &val returns the memory address of val.

This memory address is assigned to a pointer and can be shared among various functions. For example, int*p = &val will assign the memory address of val to pointer p To access the content of the memory to which the pointer points, prepend it with a *. For example, *p will return the value reflected by val and any modification to it will be reflected at the source (val ).

void increment(int *v) {
        (*v)++; 
    }
      	int main() {
        int a;
        scanf("%d", &a);
        increment(&a);
        printf("%d", a);
    	return 0;      
    }     

 

Task

 

Complete the function void update(int *a,int *b). It receives two integer pointers, int* a and int* b. Set the value of

to their sum, and to their absolute difference. There is no return value, and no return statement is needed.

  • a' = a + b
  • b' = |a  - b|

Input Format

The input will contain two integers, a and b, separated by a newline.

Output Format

Modify the two values in place and the code stub main() will print their values.

Note: Input/ouput will be automatically handled. You only have to complete the function described in the 'task' section.

Sample Input

4
5

Sample Output

9
1

Explanation

  • a' = 4 + 5 = 9
  • b' = |4 - 5| = 1

 

 

 

Code Examples

#1 Code Example with C Programming

Code - C Programming


#include <stdio.h>
#include <stdlib.h>

void update(int *a,int *b) {
    *a = *a+*b;
    *b = abs(*a-*b-*b);
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);

    return 0;
}
Copy The Code & Try With Live Editor

Input

x
+
cmd
4 5

Output

x
+
cmd
9 1
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Demonstration


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