Algorithm
Problem Name:
In this HackerRank Functions in Java programming problem solution,
You are updating the username policy on your company's internal networking platform. According to the policy, a username is considered valid if all the following constraints are satisfied:
- The username consists of 8 to 30 characters inclusive. If the username consists of less than 8 or greater than 30 characters, then it is an invalid username.
- The username can only contain alphanumeric characters and underscores (
_
). Alphanumeric characters describe the character set consisting of lowercase characters [a -z], uppercase characters [A - Z], and digits [0 - 9] - The first character of the username must be an alphabetic character, i.e., either lowercase character [a -z] or uppercase character [A - Z].
Input Format
The first line of input contains an integer n , describing the total number of usernames. Each of the next n , describing the total number of usernames. Each of the next
- 1 <= n <= 100
- The username consists of any printable characters.
Output Format
For each of the usernames, the locked stub code prints Valid
if the username is valid; otherwise Invalid
each on a new line.
Sample Input 0
8
Julia
Samantha
Samantha_21
1Samantha
Samantha?10_2A
JuliaZ007
Julia@007
_Julia007
Sample Output 0
Invalid
Valid
Valid
Invalid
Invalid
Valid
Invalid
Invalid
Explanation 0
Refer diagram in the challenge statement.
Code Examples
#1 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
class UsernameValidator {
public static final String regularExpression = "^[a-zA-Z][\\w]{7,29}$";
}
public class Solution {
private static final Scanner scan = new Scanner(System.in);
public static void main(String[] args) {
int n = Integer.parseInt(scan.nextLine());
while (n-- != 0) {
String userName = scan.nextLine();
if (userName.matches(UsernameValidator.regularExpression))
System.out.println("Valid");
else
System.out.println("Invalid");
}
}
}
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