Algorithm
Problem Name:
In this HackerRank Bitwise operators in the c programming problem solution, In this challenge, you will use logical bitwise operators. All data is stored in its binary representation. The logical operators, and C language, use 1 to represent true and 0 to represent false. The logical operators compare bits in two numbers and return true or false, 0 or 1, for each bit compared.
- Bitwise AND operator & The output of bitwise AND is 1 if the corresponding bits of two operands is 1. If either bit of an operand is 0, the result of corresponding bit is evaluated to 0. It is denoted by &.
- Bitwise OR operator | The output of bitwise OR is 1 if at least one corresponding bit of two operands is 1. It is denoted by |.
- Bitwise XOR (exclusive OR) operator ^ The result of bitwise XOR operator is 1 if the corresponding bits of two operands are opposite. It is denoted by ⊕.
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
//Complete the following function.
/*
void calculate_the_maximum(int n, int k) {
//Write your code here.
}
*/
int main() {
int n, k,e;
scanf("%d %d", &n, &k);
scanf("%d %d", &n, &k);
int mxAnd = 0, mxOr = 0, mxXor = 0;
for(int i = 1; i < = n; i++){
for(int j = i + 1; j < = n; j++){
if(mxAnd < (i & j) && (i & j) < k)
mxAnd = i & j;
if(mxOr < (i | j) && (i | j) < k)
mxOr = i | j;
if(mxXor < (i ^ j) && (i ^ j) < k)
mxXor = i ^ j;
}
}
printf("%d\n", mxAnd);
printf("%d\n", mxOr);
printf("%d\n", mxXor>;
return 0;
}
Input
5 4
Output
2
3
3