Algorithm
Problem Name: Python -
In this HackerRank Functions in PYTHON problem solution,
In this challenge, the task is to debug the existing code to successfully execute all provided test files.
Consider that vowels in the alphabet are a, e, i, o, u
and y
.
Function score_words
takes a list of lowercase words as an argument and returns a score as follows:
The score of a single word is 2 if the word contains an even number of vowels. Otherwise, the score of this word is 1 . The score for the whole list of words is the sum of scores of all words in the list.
Debug the given function score_words
such that it returns a correct score.
Your function will be tested on several cases by the locked template code.
Input Format
The input is read by the provided locked code template. In the first line, there is a single integer n denoting the number of words. In the second line, there are n space-separated lowercase words.
Constraints
- 1 <= n <= 20
- Each word has at most letters and all letters are English lowercase letters
Output Format
The output is produced by the provided and locked code template. It calls function score_words
with the list of words read from the input as the argument and prints the returned score to the output.
Sample Input 0
2
hacker book
Sample Output 0
4
Explanation 0
There are two words in the input: hacker
and book
. The score of the word hacker
is
book
is for the same reason. Thus the total score is
.
Sample Input 1
3
programming is awesome
Sample Output 1
4
Explanation 1
There are 3 words in the input: programming
, is
and awesome
. The score of programming
is 1 since it contains 3 vowels, an odd number of vowels. The score of is
is also 1 ecause it has an odd number of vowels. The score of awesome
is 2 since it contains 4 vowels, an even number of vowels. Thus, the total score is 1 + 1 + 2 = 4.
Code Examples
#1 Code Example with Python Programming
Code -
Python Programming
def is_vowel(letter):
return letter in ['a', 'e', 'i', 'o', 'u', 'y']
def score_words(words):
score = 0
for word in words:
num_vowels = 0
for letter in word:
if is_vowel(letter):
num_vowels += 1
if num_vowels % 2 == 0:
score += 2
else:
score += 1
return score
n = int(input())
words = input().split()
print(score_words(words))
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