Algorithm


 Problem Name: For Loop in C

Problem Link: https://www.hackerrank.com/challenges/for-loop-in-c/problem?isFullScreen=true

In this HackerRank Functions in C programming problem solution,

In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be executed until a terminal condition is met. They can even repeat forever if the terminal condition is never met.

 

The syntax for the for loop is:

 

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>

 

  • expression_1 is used for intializing variables which are generally used for controlling the terminating flag for the loop.
  • expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
  • expression_3 is generally used to update the flags/variables.

The following loop initializes i to 0, tests that i is less than 10, and increments i at every iteration. It will execute 10 times.

for(int i = 0; i < 10; i++) {
    ...
}

 

Task

For each integer n n the interval [a,b] (given as input) :

  • if 1 <= n <= 9, , then print the English representation of it in lowercase. That is "one" for one for 1,two for 2,and so on.
  • Else if n > 9 and it is an even number, then print "even".
  • Else if n > 9 and it is an odd number, then print "odd".

Input Format

The first line contains an integer, a.

The seond line contains an integer, b.

Constraints

1 <= a <= b <= 10sqrt6

Output Format

Print the appropriate English representation,even, or odd, based on the conditions described in the 'task' section.

 

Sample Input

8
11

Sample Output

eight
nine
even
odd

 

 

 

 

 

Code Examples

#1 Code Example with C Programming

Code - C Programming


#include <stdio.h>
int main()
{
    int i,j,k;
    int a,b;
    char *ch[]={"null","one","two","three","four","five",
    "six","seven","eight","nine"};
    scanf("%d%d",&a,&b);

    for(i=a;i < =b;i++)
    {
        if(i>9 && i%2)
            printf("odd\n");
        else if(i>9 && i%2==0)
            printf("even\n");
        else
            printf("%s\n",ch[i]);

    }
    return 0;
}
Copy The Code & Try With Live Editor

Input

x
+
cmd
8 11

Output

x
+
cmd
eight nine even odd
Advertisements

Demonstration


Previous
[Solved] Conditional Statements in C in C solution in Hackerrank - Hacerrank solution C
Next
[Solved] Sum of Digits of a Five Digit Number in C solution in Hackerrank - Hacerrank solution C