Algorithm


Problem Name: Data Structures - Tree: Inorder Traversal

Problem Link: https://www.hackerrank.com/challenges/tree-inorder-traversal/problem?isFullScreen=true

In this HackerRank in Data Structures - Tree: Inorder Traversal solutions

In this challenge, you are required to implement inorder traversal of a tree.

Complete the inOrder function in your editor below, which has 1 parameter: a pointer to the root of a binary tree. It must print the values in the tree's inorder traversal as a single line of space-separated values.

Input Format

Our hidden tester code passes the root node of a binary tree to your $inOrder* function.

Constraints

1 <= Nodes in the tree

Output Format

Print the tree's inorder traversal as a single line of space-separated values.

Sample Input

     1
      \
       2
        \
         5
        /  \
       3    6
        \
         4  

Sample Output

1 2 3 4 5 6 

Explanation

The tree's inorder traversal results in 1 2 3 4 5 6 as the required result.

<= 500

 

 

Code Examples

#1 Code Example with C Programming

Code - C Programming


#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

struct node {
    
    int data;
    struct node *left;
    struct node *right;
  
};

struct node* insert( struct node* root, int data ) {
		
	if(root == NULL) {
	
        struct node* node = (struct node*)malloc(sizeof(struct node));

        node->data = data;

        node->left = NULL;
        node->right = NULL;
        return node;
	  
	} else {
      
		struct node* cur;
		
		if(data  < = root->data) {
            cur = insert(root->left, data);
            root->left = cur;
		} else {
            cur = insert(root->right, data);
            root->right = cur;
		}
	
		return root;
	}
}

/* you only have to complete the function given below.  
node is defined as  

struct node {
    
    int data;
    struct node *left;
    struct node *right;
  
};

*/
void inOrder( struct node *root) {
    if (root != NULL) {
        inOrder(root->left);
        printf("%d ", root->data);
        inOrder(root->right);
    }
}


int main() {
  
    struct node* root = NULL;
    
    int t;
    int data;

    scanf("%d", &t);

    while(t-- > 0) {
        scanf("%d", &data);
        root = insert(root, data);
    }
  
	inOrder(root);
    return 0;
}

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#2 Code Example with C++ Programming

Code - C++ Programming


#include <bits/stdc++.h>

using namespace std;

class Node {
    public:
        int data;
        Node *left;
        Node *right;
        Node(int d) {
            data = d;
            left = NULL;
            right = NULL;
        }
};

class Solution {
    public:
        Node* insert(Node* root, int data) {
            if(root == NULL) {
                return new Node(data);
            } else {
                Node* cur;
                if(data  < = root->data) {
                    cur = insert(root->left, data);
                    root->left = cur;
                } else {
                    cur = insert(root->right, data);
                    root->right = cur;
               }

               return root;
           }
        }


    void inOrder(Node *root) {
    if(root == NULL){
        return;
    }
    inOrder(root->left);
    printf("%d ", root->data);
    inOrder(root->right);
    
}

}; //End of Solution

int main() {
  
    Solution myTree;
    Node* root = NULL;
    
    int t;
    int data;

    std::cin >> t;

    while(t-- > 0) {
        std::cin >> data;
        root = myTree.insert(root, data);
    }
  
    myTree.inOrder(root);
    return 0;
}
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#3 Code Example with Java Programming

Code - Java Programming


import java.util.*;
import java.io.*;

class Node {
    Node left;
    Node right;
    int data;
    
    Node(int data) {
        this.data = data;
        left = null;
        right = null;
    }
}

class Solution {


    public static void inOrder(Node root) {
    if(root!=null)
    {
        if(root.left!=null)
        {
            inOrder(root.left);
        }
        
        System.out.print(root.data + " ");
        
        if(root.right!=null)
        {
            inOrder(root.right);
        }
    }
}

    public static Node insert(Node root, int data) {
        if(root == null) {
            return new Node(data);
        } else {
            Node cur;
            if(data <= root.data) {
                cur = insert(root.left, data);
                root.left = cur;
            } else {
                cur = insert(root.right, data);
                root.right = cur;
            }
            return root;
        }
    }

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int t = scan.nextInt(>;
        Node root = null;
        while(t-- > 0) {
            int data = scan.nextInt();
            root = insert(root, data);
        }
        scan.close();
        inOrder(root);
    }   
}
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#4 Code Example with Python Programming

Code - Python Programming


class Node:
    def __init__(self, info): 
        self.info = info  
        self.left = None  
        self.right = None 
        self.level = None 

    def __str__(self):
        return str(self.info) 

class BinarySearchTree:
    def __init__(self): 
        self.root = None

    def create(self, val):  
        if self.root == None:
            self.root = Node(val)
        else:
            current = self.root
         
            while True:
                if val < current.info:
                    if current.left:
                        current = current.left
                    else:
                        current.left = Node(val)
                        break
                elif val > current.info:
                    if current.right:
                        current = current.right
                    else:
                        current.right = Node(val)
                        break
                else:
                    break

"""
Node is defined as
self.left (the left child of the node)
self.right (the right child of the node)
self.info (the value of the node)
"""
def inOrder(root):
    if root:
        inOrder(root.left)
        print(root.info, end=" ")
        inOrder(root.right)



tree = BinarySearchTree()
t = int(input())

arr = list(map(int, input().split()))

for i in range(t):
    tree.create(arr[i])

inOrder(tree.root)
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