Algorithm
Problem Name:
In this HackerRank Functions in Java programming problem solution,
Java Iterator class can help you to iterate through every element in a collection. Here is a simple example:
import java.util.*;
public class Example{
public static void main(String []args){
ArrayList mylist = new ArrayList();
mylist.add("Hello");
mylist.add("Java");
mylist.add("4");
Iterator it = mylist.iterator();
while(it.hasNext()){
Object element = it.next();
System.out.println((String)element);
}
}
}
In this problem you need to complete a method func. The method takes an ArrayList as input. In that ArrayList there is one or more integer numbers, then there is a special string "###", after that there are one or more other strings. A sample ArrayList may look like this:
element[0]=>42
element[1]=>10
element[2]=>"###"
element[3]=>"Hello"
element[4]=>"Java"
You have to modify the func method by editing at most 2 lines
so that the code only prints the elements after the special string "###". For the sample above the output will be:
Hello
Java
Note: The stdin doesn't contain the string "###", it is added in the main method.
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Code Examples
#1 Code Example with Java Programming
Code -
Java Programming
import java.util.*;
public class Main{
static Iterator func(ArrayList mylist){
Iterator it=mylist.iterator();
while(it.hasNext()){
Object element = it.next();
if (element.equals("###"))
break;
}
return it;
}
@SuppressWarnings({ "unchecked" })
public static void main(String []args){
ArrayList mylist = new ArrayList();
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int m = sc.nextInt();
for(int i = 0; i < n; i++){
mylist.add(sc.nextInt());
}
mylist.add("###");
for(int i = 0; i < m;i++){
mylist.add(sc.next());
}
Iterator it = func(mylist);
while(it.hasNext()){
Object element = it.next();
System.out.println((String)element);
}
}
}
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