Algorithm
Problem Name: 30 days of code -
Objective
Today, we're getting started with Exceptions by learning how to parse an integer from a string and print a custom error message. Check out the Tutorial tab for learning materials and an instructional video!
Task
Read a string, S, and print its integer value; if S cannot be converted to an integer, print Bad String. Note: You must use the String-to-Integer and exception handling constructs built into your submission language. If you attempt to use loops/conditional statements, you will get a 0 score.
Input Format
A single string S.
Constraints
- 1 <= |S| <= 6, where |S| is the length of string S.
- S is composed of either lowercase letters (a - z) or decimal digits (0 - 9).
Output Format
Print the parsed integer value of S, or Bad String if S cannot be converted to an integer.
Sample Input 0
3
Sample Output 0
3
Sample Input 1
za
Sample Output 1
Bad String
Code Examples
#1 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main() {
try {
string str;
cin >> str;
int num = stoi(str);
cout << num;
}
catch (...) {
cout << "Bad String";
}
return 0;
}
#2 Code Example with C# Programming
Code -
C# Programming
using System;
class Solution
{
static void Main(String[] args)
{
var str = Console.ReadLine();
try
{
int num = int.Parse(str);
Console.WriteLine(num);
}
catch (Exception)
{
Console.WriteLine("Bad String");
}
}
}
#3 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String string = in.next();
in.close();
try {
Integer integer = Integer.parseInt(string);
System.out.println(integer);
} catch (NumberFormatException numberFormatException) {
System.out.println("Bad String");
}
}
}
#4 Code Example with Javascript Programming
Code -
Javascript Programming
'use strict';
process.stdin.resume();
process.stdin.setEncoding('utf-8');
let inputString = '';
let currentLine = 0;
process.stdin.on('data', function(inputStdin) {
inputString += inputStdin;
});
process.stdin.on('end', function() {
inputString = inputString.split('\n');
main();
});
function readLine() {
return inputString[currentLine++];
}
function main() {
const S = readLine();
try {
isNaN(Number(S)) ? error : console.log(S)
}
catch (err) {
console.log('Bad String')
}
}
#5 Code Example with Python Programming
Code -
Python Programming
try:
print(int(input().strip()))
except ValueError:
print("Bad String")