Algorithm
Problem Name: 30 days of code -
Objective
Today's challenge puts your understanding of nested conditional statements to the test. You already have the knowledge to complete this challenge, but check out the Tutorial tab for a video on testing.
Task
Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:
- If the book is returned on or before the expected return date, no fine will be charged (i.e.: fine = 0)
- If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, fine = 15 Hackos * (the number of days late).
- If the book is returned after the expected return month but still within the same calendar year as the expected return date, the fine = 500 Hackos * (the number of monthes late).
- If the book is returned after the calendar year in which it was expected, there is a fixed fine of 10000 Hackos.
Constraints
- 1 <= D <= 31
- 1 <= M <= 12
- 1 <= Y <= 3000
- It is guarenteed that the dates will be valid Gregorian calendar dates.
Sample Input
STDIN Function
----- --------
9 6 2015 day = 9, month = 6, year = 2015 (date returned)
6 6 2015 day = 6, month = 6, year = 2015 (date due)
Sample Output
45
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
int Aday, Amonth, Ayear, Eday,Emonth, Eyear;
int fine = 0;
scanf("%d %d %d %d %d %d", &Aday, &Amonth, &Ayear, &Eday, &Emonth, &Eyear);
if (Ayear == Eyear){
if (Amonth == Emonth){
fine = 15 * (Aday - Eday);
}
else {
fine = 500 * (Amonth - Emonth);
}
}
else if (Ayear > Eyear){
fine = 10000;
}
if (fine < 0){
fine = 0;
}
printf("%d", fine);
return 0;
}
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main() {
int da, ma, ya;
cin >> da;
cin >> ma;
cin >> ya;
int de, me, ye;
cin >> de;
cin >> me;
cin >> ye;
int fine = 0;
if (ya > ye) fine = 10000;
else if (ya == ye) {
if (ma > me) fine = (ma - me) * 500;
else if (ma == me && da > de) fine = (da - de) * 15;
}
cout << fine;
}
#3 Code Example with C# Programming
Code -
C# Programming
using System;
class Solution
{
static void Main(String[] args)
{
var actually = Console.ReadLine().Split(' ');
var da = int.Parse(actually[0]);
var ma = int.Parse(actually[1]);
var ya = int.Parse(actually[2]);
var expected = Console.ReadLine().Split(' ');
var de = int.Parse(expected[0]);
var me = int.Parse(expected[1]);
var ye = int.Parse(expected[2]);
var fine = 0;
if (ya > ye) fine = 10000;
else if (ya == ye)
{
if (ma > me) fine = (ma - me) * 500;
else if (ma == me && da > de) fine = (da - de) * 15;
}
Console.WriteLine(fine);
}
}
#4 Code Example with Golang Programming
Code -
Golang Programming
package main
import "fmt"
func fineCalculator(actualDay, actualMonth, actualYear, expectedDay, expectedMonth, expectedYear int) int {
if actualYear < expectedYear {
return 0
}
if actualYear > expectedYear {
return 10000
}
if actualMonth < expectedMonth {
return 0
}
if actualMonth > expectedMonth {
return (actualMonth - expectedMonth) * 500
}
if actualDay < expectedDay {
return 0
}
if actualDay > expectedDay {
return (actualDay - expectedDay) * 15
}
return 0
}
func main() {
var actualDay, actualMonth, actualYear int
var expectedDay, expectedMonth, expectedYear int
fmt.Scan(&actualDay)
fmt.Scan(&actualMonth)
fmt.Scan(&actualYear)
fmt.Scan(&expectedDay)
fmt.Scan(&expectedMonth)
fmt.Scan(&expectedYear)
result := fineCalculator(actualDay, actualMonth, actualYear, expectedDay, expectedMonth, expectedYear)
fmt.Println(result)
}
#5 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int da = in.nextInt();
int ma = in.nextInt();
int ya = in.nextInt();
int de = in.nextInt();
int me = in.nextInt();
int ye = in.nextInt();
int fine = 0;
if (ya > ye) fine = 10000;
else if (ya == ye) {
if (ma > me) fine = (ma - me) * 500;
else if (ma == me && da > de) fine = (da - de) * 15;
}
System.out.println(fine);
}
}
#6 Code Example with Javascript Programming
Code -
Javascript Programming
function processData(input) {
//Enter your code here
const [d1,m1,y1,d2,m2,y2] = input.split(/\s/).map(Number);
if (y1 !== y2) console.log(y1 > y2 ? 10000 : 0);
else if(m1 !== m2) console.log(m1 > m2 ? (m1 - m2) * 500 : 0);
else console.log(d1 > d2 ? (d1 - d2) * 15 : 0);
}
process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});
process.stdin.on("end", function () {
processData(_input);
});
#7 Code Example with Python Programming
Code -
Python Programming
actually = list(map(int, input().split()))
da, ma, ya = actually
expected = list(map(int, input().split()))
de, me, ye = expected
fine = 0
if ya > ye:
fine = 10000
elif ya == ye:
if ma > me:
fine = (ma - me) * 500
elif ma == me and da > de:
fine = (da - de) * 15
print(fine)
#8 Code Example with PHP Programming
Code -
PHP Programming
0 ? 15 * ($d1 - $d2) : 0;
$m = 500 * ($m1 - $m2) > 0 ? 500 * ($m1 - $m2) : 0;
$y = $y1 - $y2 > 0 ? 10000 : 0;
if ($y > 0) {
return $y;
}
if ($m > 0) {
return $m;
}
if ($d > 0) {
return $d + $m + $y;
}
return 0;
}
$_fp = fopen("php://stdin", "r");
fscanf($_fp, "%[^\n]", $date1);
fscanf($_fp, "%[^\n]", $date2);
$date1 = date_parse_from_format('j m Y', $date1);
$date2 = date_parse_from_format('j m Y', $date2);
echo libraryFine($date1['day'], $date1['month'], $date1['year'], $date2['day'], $date2['month'], $date2['year']);
?>