[Solved] Mini-Max Sum in C, C++,Java, JavaScript, Python, PHP & C# solution in Hackerrank

#1 Code Example with C Programming

Code - C Programming

#include <stdio.h>

int main() {
    long long a[5];
    scanf("%lld %lld %lld %lld %lld", &a[0], &a[1], &a[2], &a[3], &a[4]);
    
    long long tot = 0;
    long long max = 0;
    long long min = 1000000000;
    int i;
    for (i = 0; i  <  5; ++i) {
        tot += a[i];
        if (a[i] > max) max = a[i];
        if (a[i]  <  min) min = a[i];
    }
    printf("%lld %lld", tot-max, tot-min);
}

#2 Code Example with C++ Programming

Code - C++ Programming

#include <iostream>
using namespace std;

int main() {
  int a[5];
  for (int i = 0; i  <  5; i++) {
    cin >> a[i];
  }
  int minVal = a[0], maxVal = a[0];
  long long sum = a[0];
  for (int i = 1; i  <  5; i++) {
    minVal = min(minVal, a[i]);
    maxVal = max(maxVal, a[i]);
    sum += a[i];
  }
  cout << sum - maxVal << " " << sum - minVal << endl;
  return 0;
}

#3 Code Example with Java Programming

Code - Java Programming

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        
        long min = Long.MAX_VALUE;
        long max = 0;
        long sum = 0;
        for(int i=0; i < 5; i++)
        {
            long curr = in.nextLong();  
            if(max < curr>
            {
                max = curr;
            }
            if(min > curr)
            {
                min = curr;
            }
            
            sum += curr;
        }
        long minSum = sum - max;//Removes the largest of the 5 numbers to get the min sum
        long maxSum = sum - min;//Removes the smallest of the 5 numbers to get the max sum
        System.out.println(minSum + " " + maxSum);
    }
}

#4 Code Example with Javascript Programming

Code - Javascript Programming

'use strict';

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
    inputString += inputStdin;
});

process.stdin.on('end', _ => {
    inputString = inputString.replace(/\s*$/, '')
        .split('\n')
        .map(str => str.replace(/\s*$/, ''));

    main();
});

function readLine() {
    return inputString[currentLine++];
}

// Complete the miniMaxSum function below.
function miniMaxSum(arr) {
    arr.sort((a, b) => a - b)
    let first = arr.slice(0, -1);
    let last = arr.slice(1)

    let minSum = first.reduce((a, b) => a + b, 0);
    let maxSum = last.reduce((a, b) => a + b, 0);

    console.log(minSum + " " + maxSum)

}

function main() {
    const arr = readLine().split(' ').map(arrTemp => parseInt(arrTemp, 10));

    miniMaxSum(arr);
}

#5 Code Example with Python Programming

Code - Python Programming

import math
import os
import random
import re
import sys

def miniMaxSum(arr):
    l1=[]
    for i in arr:
        x=-i
        for j in arr:
            x+=j
        l1.append(x)
    print(min(l1),max(l1))    
        

if __name__ == '__main__':
    arr = list(map(int, input().rstrip().split()))

    miniMaxSum(arr)

#6 Code Example with C# Programming

Code - C# Programming

using System;
using static System.Console;
using System.Linq;

class Solution
{

    static void Main(String[] args)
    {
        var numbers = ReadLine().Split(' ').Select(x => long.Parse(x)).ToList();
        var sumOfAllNumbers = 0L;
        var minimum = long.MaxValue;
        var maximum = 0L;
        for (int i = 0; i  <  5; i++)
        {
            sumOfAllNumbers += numbers[i];
            if (numbers[i]  <  minimum)
                minimum = numbers[i];

            if (numbers[i] > maximum)
                maximum = numbers[i];

        }
        WriteLine(string.Format("{0} {1}", sumOfAllNumbers - maximum, sumOfAllNumbers - minimum));
    }
}

#7 Code Example with PHP Programming

Code - PHP Programming