## Algorithm

A. Replacement
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

Little Petya very much likes arrays consisting of n integers, where each of them is in the range from 1 to 109, inclusive. Recently he has received one such array as a gift from his mother. Petya didn't like it at once. He decided to choose exactly one element from the array and replace it with another integer that also lies in the range from 1 to 109, inclusive. It is not allowed to replace a number with itself or to change no number at all.

After the replacement Petya sorted the array by the numbers' non-decreasing. Now he wants to know for each position: what minimum number could occupy it after the replacement and the sorting.

Input

The first line contains a single integer n (1 ≤ n ≤ 105), which represents how many numbers the array has. The next line contains n space-separated integers — the array's description. All elements of the array lie in the range from 1 to 109, inclusive.

Output

Print n space-separated integers — the minimum possible values of each array element after one replacement and the sorting are performed.

Examples
input
Copy
`51 2 3 4 5`
output
Copy
`1 1 2 3 4`
input
Copy
`52 3 4 5 6`
output
Copy
`1 2 3 4 5`
input
Copy
`32 2 2`
output
Copy
`1 2 2`

## Code Examples

### #1 Code Example with C++ Programming

```Code - C++ Programming```

``````#include <cstdio>
#include <iostream>
#include <vector>
#include <algorithm>

int main(){

long n; scanf("%ld", &n);
std::vector<long> array(n);
long maxElement(0), maxPos(0);

for(long p = 0; p < n; p++){
scanf("%ld", &array[p]);
if(array[p] > maxElement){maxElement = array[p]; maxPos = p;}
}

if(maxElement == 1){array[maxPos] = 2;}
else{array[maxPos] = 1;}

sort(array.begin(), array.end());
for(long p = 0; p < n; p++){printf("%ld ", array[p]);}

return 0;
}``````
Copy The Code &

Input

cmd
5
1 2 3 4 5

Output

cmd
1 1 2 3 4