## Algorithm

A. Life Without Zeros
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

Can you imagine our life if we removed all zeros from it? For sure we will have many problems.

In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation a + b = c, where a and b are positive integers, and c is the sum of a and b. Now let's remove all zeros from this equation. Will the equation remain correct after removing all zeros?

For example if the equation is 101 + 102 = 203, if we removed all zeros it will be 11 + 12 = 23 which is still a correct equation.

But if the equation is 105 + 106 = 211, if we removed all zeros it will be 15 + 16 = 211 which is not a correct equation.

Input

The input will consist of two lines, the first line will contain the integer a, and the second line will contain the integer b which are in the equation as described above (1 ≤ a, b ≤ 109). There won't be any leading zeros in both. The value of c should be calculated as c = a + b.

Output

The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise.

Examples
input
Copy
`101102`
output
Copy
`YES`
input
Copy
`105106`
output
Copy
`NO`

## Code Examples

### #1 Code Example with C++ Programming

```Code - C++ Programming```

``````#include <iostream>

using namespace std;

void reverse(long long &n) {
long long tmp = 0;
while(n != 0) {
tmp *= 10;
tmp += n % 10;
n /= 10;
}
n = tmp;
}

int main() {
long long a, b, c;
cin>> a>> b;
c = a + b;

long long x = a, y = b, z = c, tmp;

tmp = 0;
while(x != 0) {
if(x % 10 != 0) {
tmp *= 10;
tmp += x % 10;
}

x /= 10;
}
x = tmp;

tmp = 0;
while(y != 0) {
if(y % 10 != 0) {
tmp *= 10;
tmp += y % 10;
}

y /= 10;
}
y = tmp;

tmp = 0;
while(z != 0) {
if(z % 10 != 0) {
tmp *= 10;
tmp += z % 10;
}

z /= 10;
}
z = tmp;

reverse(x);
reverse(y);
reverse(z);

if(x + y == z) cout << "YES" << endl;
else cout << "NO" << endl;

return 0;
}``````
Copy The Code &

Input

cmd
101
102

Output

cmd
YES