Algorithm


E. Cyclic Components
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

You are given an undirected graph consisting of n vertices and m edges. Your task is to find the number of connected components which are cycles.

Here are some definitions of graph theory.

An undirected graph consists of two sets: set of nodes (called vertices) and set of edges. Each edge connects a pair of vertices. All edges are bidirectional (i.e. if a vertex a is connected with a vertex b, a vertex b is also connected with a vertex a). An edge can't connect vertex with itself, there is at most one edge between a pair of vertices.

Two vertices u and v belong to the same connected component if and only if there is at least one path along edges connecting u and v.

A connected component is a cycle if and only if its vertices can be reordered in such a way that:

  • the first vertex is connected with the second vertex by an edge,
  • the second vertex is connected with the third vertex by an edge,
  • ...
  • the last vertex is connected with the first vertex by an edge,
  • all the described edges of a cycle are distinct.

A cycle doesn't contain any other edges except described above. By definition any cycle contains three or more vertices.

There are 66 connected components, 22 of them are cycles: [7,10,16][7,10,16] and [5,11,9,15][5,11,9,15].
Input

The first line contains two integer numbers n and m (1n21051≤�≤2⋅1050m21050≤�≤2⋅105) — number of vertices and edges.

The following m lines contains edges: edge i is given as a pair of vertices vi��ui�� (1vi,uin1≤��,��≤�uivi��≠��). There is no multiple edges in the given graph, i.e. for each pair (vi,ui��,��) there no other pairs (vi,ui��,��) and (ui,vi��,��) in the list of edges.

Output

Print one integer — the number of connected components which are also cycles.

Examples
input
Copy
5 4
1 2
3 4
5 4
3 5
output
Copy
1
input
Copy
17 15
1 8
1 12
5 11
11 9
9 15
15 5
4 13
3 13
4 3
10 16
7 10
16 7
14 3
14 4
17 6
output
Copy
2
Note

In the first example only component [3,4,5][3,4,5] is also a cycle.

The illustration above corresponds to the second example.

 

Code Examples

#1 Code Example with C++ Programming

Code - C++ Programming

#include <bits/stdc++.h>

using namespace std;

int const N = 2e5 + 1;
int n, m, res;
bool vis[N];
vector<vector<int> > g;
vector<int> all;

void DFS(int u) {
  vis[u] = true;
  all.push_back(u);

  for(int i = 0;i < g[u].size(); ++i)
    if(!vis[g[u][i]])
      DFS(g[u][i]);
}

int main() {
  cin >> n >> m;
  g.resize(n);
  for(int i = 0, a, b; i < m; ++i) {
    cin >> a >> b;
    --a, --b;
    g[a].push_back(b);
    swap(a, b);
    g[a].push_back(b);
  }

  for(int i = 0; i < n; ++i) {
    if(!vis[i]) {
      all.clear();
      DFS(i);

      bool ok = true;
      for(int j = 0; j < all.size(); ++j)
        if(g[all[j]].size() != 2) {
          ok = false;
          break;
        }

      res += (ok && all.size() > 2);
    }
  }

  cout << res << endl;

  return 0;
}
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Input

x
+
cmd
5 4
1 2
3 4
5 4
3 5

Output

x
+
cmd
1
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Demonstration


Codeforces Solution-E. Cyclic Components-Solution in C, C++, Java, Python

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