## Algorithm

B. File Name
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin letters "x") in a row, the system considers that the file content does not correspond to the social network topic. In this case, the file is not sent and an error message is displayed.

Determine the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. Print 0 if the file name does not initially contain a forbidden substring "xxx".

You can delete characters in arbitrary positions (not necessarily consecutive). If you delete a character, then the length of a string is reduced by 11. For example, if you delete the character in the position 22 from the string "exxxii", then the resulting string is "exxii".

Input

The first line contains integer n (3n100)(3≤�≤100) — the length of the file name.

The second line contains a string of length n consisting of lowercase Latin letters only — the file name.

Output

Print the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. If initially the file name dost not contain a forbidden substring "xxx", print 0.

Examples
input
Copy
6xxxiii
output
Copy
1
input
Copy
5xxoxx
output
Copy
0
input
Copy
10xxxxxxxxxx
output
Copy
8
Note

In the first example Polycarp tried to send a file with name contains number 3333, written in Roman numerals. But he can not just send the file, because it name contains three letters "x" in a row. To send the file he needs to remove any one of this letters.

## Code Examples

### #1 Code Example with C++ Programming

Code - C++ Programming

#include <bits/stdc++.h>

using namespace std;

int main() {
int n;
cin >> n;
string s;
cin >> s;

while(s.length() >= 3 && s.find("xxx") != string::npos) {
int idx = s.find("xxx");
s.erase(idx, 1);
}

cout << n - s.length() << endl;

return 0;
}
Copy The Code &

Input

cmd
6
xxxiii

Output

cmd
1