Algorithm


A. 2-3 Moves
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

You are standing at the point 00 on a coordinate line. Your goal is to reach the point n�. In one minute, you can move by 22 or by 33 to the left or to the right (i. e., if your current coordinate is x�, it can become x−3�−3, x−2�−2, x+2�+2 or x+3�+3). Note that the new coordinate can become negative.

Your task is to find the minimum number of minutes required to get from the point 00 to the point n�.

You have to answer t� independent test cases.

Input

The first line of the input contains one integer t� (1≤t≤1041≤�≤104) — the number of test cases. Then t� lines describing the test cases follow.

The i�-th of these lines contains one integer n� (1≤n≤1091≤�≤109) — the goal of the i�-th test case.

Output

For each test case, print one integer — the minimum number of minutes required to get from the point 00 to the point n� for the corresponding test case.

Example
input
Copy
4
1
3
4
12
output
Copy
2
1
2
4

 



 

Code Examples

#1 Code Example with C++ Programming

Code - C++ Programming

#include<bits/stdc++.h>
using namespace std;


#define ll long long
#define endl '\n'
#define debug(n) cout<<(n)<<endl;
const ll INF = 2e18 + 99;

int main(){
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);

  int t;
  cin>>t;
  while(t--){
    int n;
    cin>>n;
    int ans;
    if(n == 1){
      ans = 2;
    }
    else if(n % 3 != 0){
      ans = n/3 + 1;
    }
    else{
      ans = n/3;
    }
    cout<<ans<<endl;
  }

}
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Input

x
–
+
cmd
4
1
3
4
12

Output

x
–
+
cmd
2
1
2
4
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Demonstration


Codeforcess Solution 1716-A A. 2-3 Moves ,C++, Java, Js and Python,1716-A,Codeforcess Solution

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