Algorithm


A. Maximum in Table
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

An n × n table a is defined as follows:

  • The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
  • Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.

These conditions define all the values in the table.

You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.

Input

The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.

Output

Print a single line containing a positive integer m — the maximum value in the table.

Examples
input
Copy
1
output
Copy
1
input
Copy
5
output
Copy
70
Note

In the second test the rows of the table look as follows:

{1, 1, 1, 1, 1}, 
{1, 2, 3, 4, 5}, 
{1, 3, 6, 10, 15}, 
{1, 4, 10, 20, 35}, 
{1, 5, 15, 35, 70}.

 

Code Examples

#1 Code Example with C++ Programming

Code - C++ Programming

#include<bits/stdc++.h>
using namespace std;


#define ll long long
#define endl '\n'
#define debug(n) cout<<(n)<<endl;
const ll INF = 2e18 + 99;

int main(){
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);

  int n;
  cin>>n;

  int a[n][n];

  for(int i = 0; i < n; i++){
    for(int j = 0; j < n; j++){
      if(i == 0 || j == 0){
        a[i][j] = 1;
      }
      else{
        a[i][j] = a[i-1][j] + a[i][j-1];
      }
    }
  }
  cout<<a[n-1][n-1];
}
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Input

x
+
cmd
1

Output

x
+
cmd
1
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Demonstration


Codeforcess Solution 509-A A. Maximum in Table ,C++, Java, Js and Python ,509-A,Codeforcess Solution

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