Algorithm


A. Next Round
time limit per test
3 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

"Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.

A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).

Output

Output the number of participants who advance to the next round.

Examples
input
Copy
8 5
10 9 8 7 7 7 5 5
output
Copy
6
input
Copy
4 2
0 0 0 0
output
Copy
0
Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.



 

Code Examples

#1 Code Example with C++ Programming

Code - C++ Programming

#include<iostream>
using namespace std;

int main(){
  int n;
  int k;
  int count;
  cin>>n;
  cin>>k;
  int arr[n];
  for(int i = 0; i < n; i++){
    cout<<"i:"<<i<<" ";
    cin>>arr[i];
  }
  int quali = 0, m;
  if(arr[k-1] == 0){

    for(m = k-2; m >= 0; m--){

      if(arr[m] > 0){
      
        quali = arr[m];
        count  = m+1;
        cout<<count;
        return 0;
      }
    }
    if(quali == 0){
      cout<<0;
      return 0;
    }
  }
  else{
    quali = arr[k-1];
    count = k;
  }
  cout<<endl;
  int j = count-2;
  while(true){
    if(arr[j] == quali){
      count++;
    }
    else{
      break;
    }
    j--;
  }
  cout<<count;
  return 0;
}
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Input

x
+
cmd
8 5
10 9 8 7 7 7 5 5

Output

x
+
cmd
6
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Demonstration


Codeforcess Solution 158-A A. Next Round ,C++, Java, Js and Python ,158-A,Codeforcess Solution

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