## Algorithm

Problem Name: beecrowd | 1011

# Sphere

Adapted by Neilor Tonin, URI Brazil

Timelimit: 1

Make a program that calculates and shows the volume of a sphere being provided the value of its radius (R) . The formula to calculate the volume is: (4/3) * pi * R3. Consider (assign) for pi the value 3.14159.

Tip: Use (4/3.0) or (4.0/3) in your formula, because some languages (including C++) assume that the division's result between two integers is another integer. :)

## Input

The input contains a value of floating point (double precision).

## Output

The output must be a message "VOLUME" like the following example with a space before and after the equal signal. The value must be presented with 3 digits after the decimal point.

 Input Samples Output Samples 3 VOLUME = 113.097

 15 VOLUME = 14137.155

 1523 VOLUME = 14797486501.627

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````

#include <stdio.h<
#include <stdio.h<
int main()
{
int a;
scanf("%i", &a);
printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3);

return 0;
}

``````
Copy The Code &

Input

cmd
3

Output

cmd
VOLUME = 113.097

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````

#include <cstdio>
#include <cmath>

int main()
{
int a;

scanf("%i", &a);
printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3);

return 0;
}

``````
Copy The Code &

Input

cmd
15

Output

cmd
VOLUME = 14137.155

### #3 Code Example with Javascript Programming

```Code - Javascript Programming```

``````
import java.util.Scanner;

public class Main {

public static void main(String[] args) {
double a;
Scanner sc = new Scanner(System.in);
a = sc.nextDouble();

System.out.printf("VOLUME = %.3f\n", (4 * 3.14159 * Math.pow(a, 3.0)) / 3);

}

}
``````
Copy The Code &

Input

cmd
1523

Output

cmd
VOLUME = 14797486501.627

### #4 Code Example with Python Programming

```Code - Python Programming```

``````
raio = int(input())

pi = 3.14159

volume = float(4.0 * pi * (raio* raio * raio) / 3)

print("VOLUME = %0.3f" %volume)
``````
Copy The Code &

Input

cmd
3

Output

cmd
VOLUME = 113.097

### #5 Code Example with C# Programming

```Code - C# Programming```

``````
printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3);
``````
Copy The Code &

Input

cmd
15

Output

cmd
VOLUME = 14137.155