Algorithm
Even or Odd
Adapted by Neilor Tonin, URI 
Brazil
Read an integer value N. After, read these N values and print a message for each value saying if this value is odd, even, positive or negative. In case of zero (0), although the correct description would be "EVEN NULL", because by definition zero is even, your program must print only "NULL", without quotes.
Input
The first line of input is an integer N (N < 10000), that indicates the total number of test cases. Each case is a integer number X (-107 < X <107)..
Output
For each test case, print a corresponding message, according to the below example. All messages must be printed in uppercase letters and always will have one space between two words in the same line.
| Input Sample | Output Sample |
|
4 |
ODD NEGATIVE |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main( ){
int N, i, x;
scanf("%d", &N);
for( i = 1; i < = N; i++){
scanf("%d", &x);
if(x == 0){
printf("NULLn");
} else if(x % 2 == 0) {
if(x > 0){
printf("EVEN POSITIVEn");
} else {
printf("EVEN NEGATIVEn");
}
} else {
if(x > 0) {
printf("ODD POSITIVEn");
} else {
printf("ODD NEGATIVEn");
}
}
}
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main()
{
int n, x;
cin >> n;
for (int i = 0; i < n; ++i)
{
cin >> x;
if(x == 0) {
cout << "NULL" << endl;
} else if(x % 2 == 0) {
if(x > 0) {
cout << "EVEN POSITIVE" << endl;
} else {
cout << "EVEN NEGATIVE" << endl;
}
} else {
if(x > 0) {
cout << "ODD POSITIVE" << endl;
} else {
cout << "ODD NEGATIVE" << endl;
}
}
}
return 0;
}
Input
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.util.*;
public class Main {
public static void main(String[] args) {
int N, i, x;
Scanner sc = new Scanner(System.in);
N = sc.nextInt();
for( i = 1; i < = N; i++) {
x = sc.nextInt();
if(x == 0) {
System.out.printf("NULLn");
} else if(x % 2 == 0) {
if(x > 0) {
System.out.printf("EVEN POSITIVEn");
} else {
System.out.printf("EVEN NEGATIVEn");
}
} else {
if(x > 0) {
System.out.printf("ODD POSITIVEn");
} else {
System.out.printf("ODD NEGATIVEn");
}
}
}
}
}
Input
Output
#4 Code Example with Python Programming
Code -
Python Programming
l=[]
a=int(input())
for n in range(1,(a+1)):
l.append(int(input()))
for n in l:
if (n%2!=0)and (n0):
print("ODD POSITIVE")
if(n%2==0)and(n0):
print("EVEN POSITIVE")
Input
Output