Algorithm
Problem Name: 2 AD-HOC - beecrowd | 1542
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/1542
Reading Books
By Normandes Jr, UFU 
Brazil
Timelimit: 3
You've started competing against your friend to see who can read more books in less time. Your friend used to read much more fast than you, until the day you realized that he'd read only small books.
So, you've decided counting how many pages each book has. And decided to increase the amount of pages read per day. Now you read 5 pages per day and finish 16 days before, if you were reading 3 pages per day. In this case, how many pages has the book?
Input
The input has many test cases. Each test has tree numbers Q (0 < Q < 20), D (0 < D < 20) and P (0 < P < 20) separated by one blank space. Q means the amount of pages read per day. D is the number of days you could speed up, if you were reading the amount of pages P. An unique 0 (zero) value means end of inputs.
Output
For each test case it should be printed how many pages the book has. Use plural appropriately in Portuguese ("pagina" or "paginas"). This number should be an integer and truncated - no rounding.
| Sample Input | Sample Output |
|
3 16 5 |
120 paginas |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(void) {
int A, B, C, N;
while (scanf("%d", &A) && A != 0) {
scanf("%d %d", &B, &C);
N = (int)((A * B * C) / (C - A));
if (N == 1) printf("1 pagina\n");
else printf("%d paginas\n", N);
}
return 0;
}
Input
0
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main(void) {
int A, B, C, N;
while (cin >> A && A != 0) {
cin >> B >> C;
N = int((A * B * C) / (C - A));
if (N == 1) cout << "1 pagina" << endl;
else cout << N << " paginas" << endl;
}
return 0;
}
Input
0
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
public class Main {
static BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
static PrintWriter out = new PrintWriter(System.out);
public static void main(String[] args) throws IOException {
String l;
int Q, D, P, pag;
while (!(l = in.readLine()).equals("0")) {
String[] parameters = l.split("\\s");
Q = Integer.parseInt(parameters[0]);
D = Integer.parseInt(parameters[1]);
P = Integer.parseInt(parameters[2]);
pag = (int) (P * D * Q) / (P - Q);
String ouput = pag + " pagina";
ouput += (pag == 1) ? "" : "s";
out.println(ouput);
}
out.close();
}
}
Input
0
Output
#4 Code Example with Javascript Programming
Code -
Javascript Programming
const { createReadStream } = require("node:fs")
const { createInterface } = require("node:readline")
//// READING FILE | STREAMS ////
class LineReader {
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
* @return {import("node:readline").ReadLine}
*/
static createReadLineInterface(path, encoding = "utf8") {
const readStreamOptions = {
encoding: encoding,
flags: "r",
emitClose: true,
autoClose: true
}
return createInterface({
input: createReadStream(path, readStreamOptions),
crlfDelay: Infinity,
terminal: false
})
}
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
*/
static create(path, encoding) {
const RLI = LineReader.createReadLineInterface(path, encoding)
let EOF = false
const nextLineGenerator = (async function* () {
for await (const line of RLI)
yield line
})()
RLI.once("close", () => { EOF = true })
return {
hasNextLine: () => !EOF,
nextLine: async (/** @type {unknown} */ fn) => {
const { value } = (await nextLineGenerator.next())
return (typeof fn === "function") ? fn(value) : value
},
close: () => RLI.close()
}
}
}
async function main() {
const PATH = "/dev/stdin"
const ENCODING = "utf8"
const output = []
const lineReader = LineReader.create(PATH, ENCODING)
const helper = (line = "") => line.split(" ", 3).map(value => Number.parseInt(value, 10))
const nextLine = lineReader.nextLine.bind(lineReader, helper)
while (lineReader.hasNextLine()) {
const [Q, D = 0, P = 0] = await nextLine()
if (Q === 0) break
const bookPagesQuantity = Math.floor((Q * D * P) / (P - Q))
output.push(
bookPagesQuantity === 1 ?
`${bookPagesQuantity} pagina` :
`${bookPagesQuantity} paginas`
)
}
if (lineReader.hasNextLine())
lineReader.close()
console.log(output.join("\n"))
}
main()
Input
0
Output
#5 Code Example with Python Programming
Code -
Python Programming
while True:
e = [int(x) for x in str(input()).split()]
if e[0] == 0: break
q = e[0]
d = e[1]
p = e[2]
n = int((q * d * p) / (p - q))
if n == 1: print('1 pagina')
else: print('{} paginas'.format(n))
Input
0
Output