Algorithm
Positives and Average
Adapted by Neilor Tonin, URI 
Brazil
Read 6 values that can be floating point numbers. After, print how many of them were positive. In the next line, print the average of all positive values typed, with one digit after the decimal point.
Input
The input consist in 6 numbers that can be integer or floating point values. At least one number will be positive.
Output
The first output value is the amount of positive numbers. The next line should show the average of the positive values typed.
| Input Sample | Output Sample |
|
7 |
4 valores positivos |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(){
float n1,total = 0,average = 0;
int totalNumber = 0;
for (int i = 1; i < = 6; i++) {
scanf("%f", &n1);
if (n1 > 0) {
totalNumber += 1;
total += n1;
}
}
average = total / totalNumber;
printf("%d valores positivosn", totalNumber);
printf("%.1fn",average);
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <cstdio>
int main()
{
double n, ctr = 0;
double tmp = 0;
for(int i = 0; i < 6; ++i)
{
scanf("%lf", &n);
if(n > 0) {
tmp += n;
ctr++;
}
}
printf("%.0lf valores positivosn%.1lfn", ctr, tmp/ctr);
return 0;
}
Input
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.io.IOException;
import java.util.Scanner;
public class Main {
public static void main(String[] args) throws IOException {
float n1,total = 0,average = 0;
int totalNumber = 0;
Scanner sc =new Scanner(System.in);
for (int i = 1; i < = 6; i++) {
n1 =sc.nextFloat();
if (n1 > 0) {
totalNumber += 1;
total += n1;
}
}
average = total / totalNumber;
System.out.print(totalNumber+" valores positivosn");
System.out.printf("%.1fn",average);
}
}
Input
Output