Algorithm
Problem Name: beecrowd | 2543
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/2543
UFPR Gaming
By Ricardo Oliveira, UFPR 
Brazil
Timelimit: 1
Like many Computer Science students, you like to play the most popular electronic games nowadays: Liga of Legendas (LOL) and Contra-Strike (CS). Although you also play LOL, what you really like to do is to use all your skills to defeat the terrorist forces in Contra-Strike! You are so good at combating terror that you are often compared with the president of the USA who announced the capture of a famous real-life terrorist.
Since your skills are beyond compare, videos of your matches (your famous gameplays) appears often in UFPR Gaming, a webpage that publishes gameplays from the students of our university.
The page publishes many videos every day. Thus, it may be hard to find and count all your videos published already. However, since you are also a programmer, you decided to write a computer program to help you with this task. Given the list of gameplays published by the page, determine how many of them are videos of you playing Contra-Strike.
Input
The input contains several test cases. The first line of each test case contains two integers N and I (1 ≤ N ≤ 104, 1000 ≤ I ≤ 9999), the number of gameplays published by the page and your university ID, respectively.
The next N lines describe the published videos. Each gameplay is described by two integers i and j (1000 ≤ i ≤ 9999, j=0 or 1), where i is the author’s university ID and j=0 if the gameplay is a Contra-Strike one, or j=1 if it is a Liga of Legendas one.
The input ends with end-of-file (EOF).
Output
For each test case, print a single line containing a number indicating how many videos of you playing Contra-Strike were published by the page.
| Input Sample | Output Sample |
|
7 5558 |
2 |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(void)
{
int i, j, n, id, count, g, ID;
while (scanf("%i %i", &n, &id) != EOF)
{
count=0;
for (i = 0; i < n; ++i)
{
scanf("%i %i", &ID, &g);
if (ID == id && g == 0)
++count;
}
printf("%i\n", count);
}
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <bits/stdc++.h>
#define read() freopen("input.txt", "r", stdin)
#define write() freopen("output.txt", "w", stdout)
using namespace std;
int main(void)
{
int n, a;
while(cin >> n >> a){
int con = 0;
for(int i = 0, b, c; i < n; i++){
cin >> b >> c;
if(b == a and !c)
con++;
}
cout << con << endl;
}
return 0;
}
Input
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
//sc.useLocale(Locale.ENGLISH);
//Locale.setDefault(new Locale("en", "US"));
while(sc.hasNext()){
int n = sc.nextInt();
int facul = sc.nextInt();
int entraf = 0;
int game = 0;
int contacs = 0;
for (int i = 0 ; i < n ; i++){
entraf = sc.nextInt();
game = sc.nextInt();
if (entraf==facul)
if (game==0)
contacs++;
}
System.out.println(contacs);
}
sc.close();
}
}
Input
Output
#4 Code Example with Javascript Programming
Code -
Javascript Programming
const { createReadStream } = require("node:fs")
const { createInterface } = require("node:readline")
//// READING FILE | STREAMS ////
class LineReader {
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
* @return {import("node:readline").ReadLine}
*/
static createReadLineInterface(path, encoding = "utf8") {
const readStreamOptions = {
encoding: encoding,
flags: "r",
emitClose: true,
autoClose: true
}
return createInterface({
input: createReadStream(path, readStreamOptions),
crlfDelay: Infinity,
terminal: false
})
}
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
*/
static create(path, encoding) {
const RLI = LineReader.createReadLineInterface(path, encoding)
let EOF = false
const nextLineGenerator = (async function* () {
for await (const line of RLI)
yield line
})()
RLI.once("close", () => { EOF = true })
return {
hasNextLine: () => !EOF,
nextLine: async (/** @type {unknown} */ fn) => {
const { value } = (await nextLineGenerator.next())
return (typeof fn === "function") ? fn(value) : value
},
close: () => RLI.close()
}
}
}
const MyGamesEnum = Object.freeze({
"CS": 0,
"LOL": 1
})
//// MAIN ////
async function main() {
const PATH = "/dev/stdin"
const ENCODING = "utf8"
const output = []
const lineReader = LineReader.create(PATH, ENCODING)
while (lineReader.hasNextLine()) {
const line = await lineReader.nextLine()
if (Boolean(line) === false) break
const [N, M] = line
.split(" ", 2)
.map(value => Number.parseInt(value, 10))
let myPublishedCSGameplays = 0
for (let k = 0; k < N; k += 1) {
const [i, j] = (await lineReader.nextLine())
.split(" ", 2)
.map(value => Number.parseInt(value, 10))
if (i === M && j === MyGamesEnum.CS)
myPublishedCSGameplays += 1
}
output.push(myPublishedCSGameplays)
}
if (lineReader.hasNextLine())
lineReader.close()
console.log(output.join("\n"))
}
main()
Input
Output
#5 Code Example with Python Programming
Code -
Python Programming
while True:
try:
q = 0
e = str(input()).split()
n = int(e[0])
i = int(e[1])
for p in range(n):
e = str(input()).split()
a = int(e[0])
b = int(e[1])
if a == i and b == 0: q += 1
print(q)
except EOFError: break
Input
Output