Algorithm
DDD
Adapted by Neilor Tonin, URI 
Brazil
Read an integer number that is the code number for phone dialing. Then, print the destination according to the following table.
If the input number isn’t found in the above table, the output must be:
DDD nao cadastrado
That means “DDD not found” in Portuguese language.
Input
The input consists in a unique integer number.
Output
Print the city name corresponding to the input DDD. Print DDD nao cadastrado if doesn't exist corresponding DDD to the typed number.
| Input Sample | Output Sample |
|
11 |
Sao Paulo |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main() {
int a;
scanf("%i", &a);
if(a == 61){
printf("Brasilia\n");
} else if(a == 71){
printf("Salvador\n");
} else if(a == 11){
printf("Sao Paulo\n");
} else if(a == 21){
printf("Rio de Janeiro\n");
} else if(a == 32){
printf("Juiz de Fora\n");
} else if(a == 19){
printf("Campinas\n");
} else if(a == 27){
printf("Vitoria\n");
} else if(a == 31){
printf("Belo Horizonte\n");
} else{
printf("DDD nao cadastrado\n");
}
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
s
#include <iostream>
using namespace std;
int main(){
int a;
cin >> a;
switch(a){
case 11:
cout << "Sao Paulo\n";
break;
case 19:
cout << "Campinas\n";
break;
case 21:
cout << "Rio de Janeiro\n";
break;
case 27:
cout << "Vitoria\n";
break;
case 31:
cout << "Belo Horizonte\n";
break;
case 32:
cout << "Juiz de Fora\n";
break;
case 61:
cout << "Brasilia\n";
break;
case 71:
cout << "Salvador\n";
break;
default:
cout << "DDD nao cadastrado\n";
break;
}
return 0;
}
Input
Output
#3 #3 Code Example with Another C++ Programming
Code -
C++ Programming
#include <cstdio>
int main()
{
int a;
scanf("%i", &a);
if(a == 61){
printf("Brasilia\n");
} else if(a == 71){
printf("Salvador\n");
}else if(a == 11){
printf("Sao Paulo\n");
} else if(a == 21){
printf("Rio de Janeiro\n");
} else if(a == 32){
printf("Juiz de Fora\n");
} else if(a == 19){
printf("Campinas\n");
} else if(a == 27){
printf("Vitoria\n");
} else if(a == 31){
printf("Belo Horizonte\n");
} else{
printf("DDD nao cadastrado\n");
}
return 0;
}
Input
Output
#4 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
public class URI_1050 {
public static void main(String[] args) {
int a;
Scanner sc = new Scanner(System.in);
a = sc.nextInt();
if(a == 61){
System.out.printf("Brasilia\n");
} else if(a == 71){
System.out.printf("Salvador\n");
} else if(a == 11){
System.out.printf("Sao Paulo\n");
} else if(a == 21){
System.out.printf("Rio de Janeiro\n");
} else if(a == 32){
System.out.printf("Juiz de Fora\n");
} else if(a == 19){
System.out.printf("Campinas\n");
} else if(a == 27){
System.out.printf("Vitoria\n");
} else if(a == 31){
System.out.printf("Belo Horizonte\n");
} else{
System.out.printf("DDD nao cadastrado\n");
}
}
}
Input
Output
#5 Code Example with Python Programming
Code -
Python Programming
entrada = int(raw_input())
if(entrada == 61):
print "Brasilia"
elif(entrada == 71):
print "Salvador"
elif(entrada == 11):
print "Sao Paulo"
elif(entrada == 21):
print "Rio de Janeiro"
elif(entrada == 32):
print "Juiz de Fora"
elif(entrada == 19):
print "Campinas"
elif(entrada == 27):
print "Vitoria"
elif(entrada == 31):
print "Belo Horizonte"
else:
print "DDD nao cadastrado"
Input
Output