Algorithm
Interval
Adapted by Neilor Tonin, URI 
Brazil
You must make a program that read a float-point number and print a message saying in which of following intervals the number belongs: [0,25] (25,50], (50,75], (75,100]. If the read number is less than zero or greather than 100, the program must print the message “Fora de intervalo” that means "Out of Interval".
The symbol '(' represents greather than. For example:
[0,25] indicates numbers between 0 and 25.0000, including both.
(25,50] indicates numbers greather than 25 (25.00001) up to 50.0000000.
Input
The input file contains a floating-point number.
Output
The output must be a message like following example.
| Input Sample | Output Sample |
|
25.01 |
Intervalo (25,50] |
|
25.00 |
Intervalo [0,25] |
|
100.00 |
Intervalo (75,100] |
|
-25.02 |
Fora de intervalo |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main()
{
float n;
scanf("%f", &n);
if(n < 0 || n > 100){
printf("Fora de intervalo\n");
}else{
if(n >= 0 && n <= 25){
printf("Intervalo [0,25]\n">;
}else if(n > 25 && n <= 50){
printf("Intervalo (25,50]\n">;
}else if(n > 50 && n <= 75){
printf("Intervalo (50,75]\n");
}else{
printf("Intervalo (75,100]\n">;
}
}
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main(){
float f;
cin >> f;
if(f < 0.0000>
cout << "Fora de intervalo\n";
else if(f >= 0.0000 && f <= 25.0000>
cout << "Intervalo [0,25]\n";
else if(f > 25.0000 && f <=50.0000>
cout << "Intervalo (25,50]\n";
else if(f > 50.0000 && f <=75.0000>
cout << "Intervalo (50,75]\n";
else if(f > 75.0000 && f <=100.0000>
cout << "Intervalo (75,100]\n";
else if(f > 100.0000)
cout << "Fora de intervalo\n";
return 0;
}
Input
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
float N;
Scanner input = new Scanner(System.in);
N = input.nextFloat();
if (N >= 0) && < = 25.0000 {
System.out.printf("Intervalo [0,25]\n");
} else if (N >= 25.00001) && <= 50.0000000 {
System.out.printf("Intervalo [25,50]\n");
} else if (N >= 50.00001) && < = 75.0000000 {
System.out.printf("Intervalo [0,25]\n");
} else if (N >= 75.00001) && <= 100.0000000 {
System.out.print("Intervalo [75,100]\n");
} else {
System.out.print("Fora de intervalo\n");
}
}
}
Input
Output
#4 Code Example with Python Programming
Code -
Python Programming
X = float(input())
if X>75 and X<=100:
print("Intervalo (75,100]")
elif X>50 and X<=75:
print("Intervalo (50,75]")
elif X>25 and X<=50:
print("Intervalo (25,50]")
elif X>=0 and X<=25:
print("Intervalo [0,25]")
else:
print("Fora de intervalo")
Input
Output