## Algorithm

Problem Name: beecrowd | 1037

# Interval

Adapted by Neilor Tonin, URI Brazil

Timelimit: 1

You must make a program that read a float-point number and print a message saying in which of following intervals the number belongs: [0,25] (25,50], (50,75], (75,100]. If the read number is less than zero or greather than 100, the program must print the message “Fora de intervalo” that means "Out of Interval".

The symbol '(' represents greather than. For example:
[0,25] indicates numbers between 0 and 25.0000, including both.
(25,50] indicates numbers greather than 25 (25.00001) up to 50.0000000.

## Input

The input file contains a floating-point number.

## Output

The output must be a message like following example.

 Input Sample Output Sample 25.01 Intervalo (25,50]

 25 Intervalo [0,25]

 100 Intervalo (75,100]

 -25.02 Fora de intervalo

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````

#include <stdio.h>

int main()
{
float n;
scanf("%f", &n);

if(n  <  0 || n > 100){
printf("Fora de intervalo\n");
}else{
if(n >= 0 && n <= 25){
printf("Intervalo [0,25]\n">;
}else if(n > 25 && n <= 50){
printf("Intervalo (25,50]\n">;
}else if(n > 50 && n <= 75){
printf("Intervalo (50,75]\n");
}else{
printf("Intervalo (75,100]\n">;
}
}

return 0;
}
``````
Copy The Code &

Input

cmd
25.01

Output

cmd
Intervalo (25,50]

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````

#include <iostream>

using namespace std;

int main(){

float f;

cin >> f;

if(f < 0.0000>
cout << "Fora de intervalo\n";
else if(f >= 0.0000 && f <= 25.0000>
cout << "Intervalo [0,25]\n";
else if(f > 25.0000 && f <=50.0000>
cout << "Intervalo (25,50]\n";
else if(f > 50.0000 && f <=75.0000>
cout << "Intervalo (50,75]\n";
else if(f > 75.0000 && f <=100.0000>
cout << "Intervalo (75,100]\n";
else if(f > 100.0000)
cout << "Fora de intervalo\n";

return 0;
}
``````
Copy The Code &

Input

cmd
25.00

Output

cmd
Intervalo [0,25]

### #3 Code Example with Java Programming

```Code - Java Programming```

``````

import java.util.Scanner;

public class Main {
public static void main(String[] args) {
float N;
Scanner input = new Scanner(System.in);
N = input.nextFloat();

if (N >= 0) &&  < = 25.0000 {
System.out.printf("Intervalo [0,25]\n");
} else if (N >= 25.00001) && <= 50.0000000 {
System.out.printf("Intervalo [25,50]\n");
} else if (N >= 50.00001) &&  < = 75.0000000 {
System.out.printf("Intervalo [0,25]\n");
} else if (N >= 75.00001) && <= 100.0000000 {
System.out.print("Intervalo [75,100]\n");
} else {
System.out.print("Fora de intervalo\n");
}
}
}
``````
Copy The Code &

Input

cmd
100.00

Output

cmd
Intervalo (75,100]

### #4 Code Example with Python Programming

```Code - Python Programming```

``````

X = float(input())
if X>75 and X<=100:
print("Intervalo (75,100]")
elif X>50 and X<=75:
print("Intervalo (50,75]")
elif X>25 and X<=50:
print("Intervalo (25,50]")
elif X>=0 and X<=25:
print("Intervalo [0,25]")
else:
print("Fora de intervalo")
``````
Copy The Code &

Input

cmd
-25.02

Output

cmd
Fora de intervalo