Algorithm
Average 1
Adapted by Neilor Tonin, URI 
Brazil
Read two floating points' values of double precision A and B, corresponding to two student's grades. After this, calculate the student's average, considering that grade A has weight 3.5 and B has weight 7.5. Each grade can be from zero to ten, always with one digit after the decimal point. Don’t forget to print the end of line after the result, otherwise you will receive “Presentation Error”. Don’t forget the space before and after the equal sign.
Input
The input file contains 2 floating points' values with one digit after the decimal point.
Output
Print the message "MEDIA"(average in Portuguese) and the student's average according to the following example, with 5 digits after the decimal point and with a blank space before and after the equal signal.
| Input Samples | Output Samples |
|
5.0 |
MEDIA = 6.43182 |
|
0.0 |
MEDIA = 4.84091 |
|
10.0 |
MEDIA = 10.00000 |
Main Algorithm to solve URI 1005
(x*3.5+y*7.5) / (3.5+7.5)
Code Examples
#1 URI Online Judge Solution 1005 using C Programming Example
Code -
C Programming
#include <stdio.h>
int main(){
float x,y;
scanf("%f %f", &x, &y);
printf("MEDIA = %.5fn", (x*3.5+y*7.5)/(3.5+7.5));
return 0;
}
Input
7.1
Output
#2 URI Online Judge Solution 1005 using C++ Programming Example
Code -
C++ Programming
#include <cstdio>
int main()
{
double a,b,m;
scanf("%lf %lf", &a, &b);
m = (a/11 * 3.5) + (b/11 * 7.5);
printf("MEDIA = %.5lfn", m);
return 0;
}
Input
7.1
Output
#3 URI Online Judge Solution 1005 using Java Programming Example
Code -
Java Programming
import java.util.Scanner;
public class URI_1005 {
public static void main(String[] args){
float a, b, m;
Scanner sc = new Scanner(System.in);
a = sc.nextFloat();
b = sc.nextFloat();
m = (float) ((a/11 * 3.5) + (b/11 * 7.5));
System.out.printf("MEDIA = %.5fn", m);
}
}
Input
10.0
Output
#4 URI Online Judge Solution 1005 using Python Programming Example
Code -
Python Programming
nota1 = float(input())
nota2 = float(input())
media = (((nota1 * 3.5) + (nota2 * 7.5)) / 11)
print("MEDIA = %0.5f" %media)
Input
10.0
Output
#5 URI Online Judge Solution 1005 using C# Programming Example
Code -
C++ Programming
using System;
class URI {
static void Main(string[] args) {
double a, b;
a = Convert.ToDouble(Console.ReadLine());
b=Convert.ToDouble(Console.ReadLine());
Console.WriteLine("MEDIA = " + ((a*3.5 + b*7.5)/(3.5+7.5)).ToString("0.00000"));
Console.ReadKey();
}
}
Input
7.1
Output
Demonstration
URI Online Judge Solution 1005 Average 1 – Solution in C, C++, Java, Python and C#