## Algorithm

URI Problem 1002 Online Linkhttps://www.urionlinejudge.com.br/judge/en/problems/view/1002

Algorithm -

We know `Pi = 3.14159`

1. Take input the radius - `R`
2. `Area = Pi * R2`
3. Print as float Upto 4 decimal
4. Must use return with a new line `\n`

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````#include<stdio.h>
int main()
{
double R, A;
scanf("%lf", &R);
A = 3.14159 * R * R;
printf("A=%.4lf\n", A);
return 0;
}``````
Copy The Code &

Input

cmd
2.00

Output

cmd
A=12.5664

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````#include <iostream>
#include <iomanip>
using namespace std;

int main(){
double R,A;
cin >> R;
A = 3.14159 * R * R;
cout << "A=" << fixed << setprecision(4) << A << endl;
return 0;
}``````
Copy The Code &

Input

cmd
100.64

Output

cmd
A=31819.3103

### #3 Code Example with Java Programming

```Code - Java Programming```

``````import java.util.Scanner;

public class Main {
public static void main(String[] args){
double R,A;
Scanner sc = new Scanner(System.in);
R = sc.nextDouble();
A = 3.14159 * R * R;
System.out.printf("A=%.4f\n",  A);
}
}``````
Copy The Code &

Input

cmd
150.00

Output

cmd
A=70685.7750

### #4 Code Example with Python Programming

```Code - Python Programming```

``````R = float(input())

Area =  3.14159 * R * R

print("A=%0.4f" %Area)``````
Copy The Code &

Input

cmd
4

Output

cmd
A=50.2654

### #5 C# Example Solution URI 1002

```Code - C Programming```

``````using System;
class URI {

static void Main(string[] args) {
area = 3.14159 * (radio * radio);
Console.WriteLine("A="+area.ToString("0.0000"));
}
}``````
Copy The Code &

Input

cmd
5

Output

cmd
A=78.5397

## Demonstration

URI Online Judge | 1002

# Area of a Circle

Adapted by Neilor Tonin, URI Brazil

Timelimit: 1

The formula to calculate the area of a circumference is defined as A = π . R2. Considering to this problem that π = 3.14159:

Calculate the area using the formula given in the problem description.

## Input

The input contains a value of floating point (double precision), that is the variable R.

## Output

Present the message "A=" followed by the value of the variable, as in the example bellow, with four places after the decimal point. Use all double precision variables. Like all the problems, don't forget to print the end of line after the result, otherwise you will receive "Presentation Error".

 Input Samples Output Samples 2.00 A=12.5664
 100.64 A=31819.3103
 150 A=70685.7750