Algorithm
Problem Name: beecrowd | 2685
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/2685
The Change
By Samuel Lucas Santos Gomes, IFSULDEMINAS 
Brazil
Timelimit: 1
Julio is creating a new SmartWatch, especially for programmers. It's amazing the advantages he offers and the comfort that he has to code. The clock still been in development and he promised to fix the bugs and put some better gear and, in return, he asked for a simple system for Stand Bay mode. The problem is the clock itself always has the inclination angle of the Sun/Moon (0 to 360). Given a clock, your mission is, if you want to accept: given in degrees the inclination of the Sun/Moon in relation to the Earth, tell what period of the day it is.
Input
The input contains an integer M (0 ≤ M ≤ 360) representing the degree of the Sun/Moon. As the position changes constantly, your program will receive several cases every second (EOF).
Output
Print a greeting for the time of day it is: "Boa Tarde!!"(Good Afternoon!!), "Boa Noite!!"(Good Night!!), "Bom Dia!!"(Good Morning) and "De Madrugada!!"(Dawn!!).
| Input Sample | Output Sample |
|
0 |
Bom Dia!! |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(void)
{
int n;
while (scanf("%i", &n) != EOF)
{
if (n < 90 || n==360)
printf("Bom Dia!!\n");
else if (n < 180)
printf("Boa Tarde!!\n");
else if (n < 270)
printf("Boa Noite!!\n");
else if (n<360)
printf("De Madrugada!!\n");
}
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main(){
int m;
while(cin >> m){
if (m >= 0 and m < 90 or m == 360) {
cout << "Bom Dia!!" << endl;
}else if (m >= 90 and m < 180) {
cout << "Boa Tarde!!" << endl;
}else if (m >= 180 and m < 270) {
cout << "Boa Noite!!" << endl;
}else {
cout << "De Madrugada!!" << endl;
}
}
return 0;
}
Input
Output
#3 Code Example with Python Programming
Code -
Python Programming
while True:
try:
n = int(input())
if ((n >= 0 and n < 90) or n == 360):
print('Bom Dia!!')
elif (n >=90 and n < 180):
print('Boa Tarde!!')
elif (n >= 180 and n < 270):
print('Boa Noite!!')
elif (n >= 270 and n < 360):
print('De Madrugada!!')
except EOFError:
break
Input
Output
#4 Code Example with Javascript Programming
Code -
Javascript Programming
const { createReadStream } = require("node:fs")
const { createInterface } = require("node:readline")
//// READING FILE | STREAMS ////
class LineReader {
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
* @return {import("node:readline").ReadLine}
*/
static createReadLineInterface(path, encoding = "utf8") {
const readStreamOptions = {
encoding: encoding,
flags: "r",
emitClose: true,
autoClose: true
}
return createInterface({
input: createReadStream(path, readStreamOptions),
crlfDelay: Infinity,
terminal: false
})
}
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
*/
static create(path, encoding) {
const RLI = LineReader.createReadLineInterface(path, encoding)
let EOF = false
const nextLineGenerator = (async function* () {
for await (const line of RLI)
yield line
})()
RLI.once("close", () => { EOF = true })
return {
hasNextLine: () => !EOF,
nextLine: async (/** @type {unknown} */ fn) => {
const { value } = (await nextLineGenerator.next())
return (typeof fn === "function") ? fn(value) : value
},
close: () => RLI.close()
}
}
}
//// MAIN ////
async function main() {
const PATH = "/dev/stdin"
const ENCODING = "utf8"
const output = []
const lineReader = LineReader.create(PATH, ENCODING)
while (lineReader.hasNextLine()) {
const angle = Number.parseInt(await lineReader.nextLine(), 10) % 360
if (Number.isNaN(angle)) break /// EOFile Condition
if (angle >= 0 && angle < 90) output.push("Bom Dia!!")
else if (angle < 180) output.push("Boa Tarde!!")
else if (angle < 270) output.push("Boa Noite!!")
else if (angle < 360) output.push("De Madrugada!!")
}
if (lineReader.hasNextLine())
lineReader.close()
console.log(output.join("\n"))
}
main()
Input
Output