## Algorithm

Problem Name: 2 AD-HOC - beecrowd | 1329

Maratona de Programacao da SBC 2004, Warm-Up Brazil

Timelimit: 1

John and Mary have been friends since nursery school. Since then, they have shared a playful routine: every time they meet, they play Head or Tail with a coin, and whoever wins has the priviledge of deciding what they are going to play during the day. Mary always choose Head, and John always choose Tail.

Nowadays they are in college, but continue being truly good friends. Whenever they meet, they still play Head and Tail, and the winner decides which film to watch, or which restaurant to have dinner together, and so on.

Yesterday Mary confided to John that she has being keeping a record of the results of every play since they started, in nursery school. It came as a surprise to John! But since John is studying Computer Science, he decided it was a good opportunity to show Mary his skills in programming, by writing a program to determine the number of times each of them won the game over the years.

## Input

The input contains several test cases. The first line of a test case contains a single integer N indicating the number of games played (1 ≤ N ≤ 10000). The following line contains N integers Ri, separated by space, describing the list of results. If Ri = 0 it means Mary won the ith game, if Ri = 1 it means John won the ith game (1 ≤ iN). The end of input is indicated by N = 0.

## Output

For each test case in the input your program should output a line containing the sentence "Mary won X times and John won Y times", where 0 ≤ X and 0 ≤ Y.

 Sample Input Sample Output 5 0 0 1 0 1 6 0 0 0 0 0 1 0 Mary won 3 times and John won 2 times Mary won 5 times and John won 1 times

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````
#include <stdio.h>
#include <stdbool.h>

int main (void)
{

unsigned char numero;
unsigned short mary = 0, john = 0, casos;

while (true)
{

scanf("%hu", &casos);

if (casos == 0)
break;

mary = john = 0;
while (casos--)
{

scanf("%hhd", &numero);

if (numero == 0)
mary++;
else
john++;
}

printf("Mary won %hu times and John won %hu times\n", mary, john);

}
}
``````
Copy The Code &

Input

cmd
5
0 0 1 0 1
6
0 0 0 0 0 1
0

Output

cmd
Mary won 3 times and John won 2 times
Mary won 5 times and John won 1 times

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include <iostream>

using namespace std;

int main(void) {
int q, n, m, j, i;
while (cin >> q && q != 0) {
m = j = 0;
for (i = 0; i  <  q; ++i) {
cin >> n;
if (n) ++j;
else ++m;
}
cout << "Mary won " << m << " times and John won " << j << " times" << endl;
}
return 0;
}

``````
Copy The Code &

Input

cmd
5
0 0 1 0 1
6
0 0 0 0 0 1
0

Output

cmd
Mary won 3 times and John won 2 times
Mary won 5 times and John won 1 times

### #3 Code Example with Java Programming

```Code - Java Programming```

``````
import java.util.*;

public class Main {
public static void main(String[] args) throws Exception {
while(n !=0){
int m = 0, j =0;
for(int i = 0; i  <  n; i++){
if(p == 0)
m++;
else
j++;
}
System.out.println("Mary won "+m+" times and John won "+j+" times");
}
}
}
``````
Copy The Code &

Input

cmd
5
0 0 1 0 1
6
0 0 0 0 0 1
0

Output

cmd
Mary won 3 times and John won 2 times
Mary won 5 times and John won 1 times

### #4 Code Example with Javascript Programming

```Code - Javascript Programming```

``````
const { readFileSync } = require("fs")

function main() {
const responses = []

for (let index = 0; index  <  input.length; index += 2) {
const numGames = input[index]

if (numGames == "0") break

const scoreboard = input[index + 1].split(" ").reduce((wons, value) => {
if (value === "0") wons.mary += 1
else if (value === "1") wons.john += 1

return wons
}, { mary: 0, john: 0 })

responses.push(
`Mary won \${scoreboard.mary} times and John won \${scoreboard.john} times`
)
}

console.log(responses.join("\n"))
}

main()
``````
Copy The Code &

Input

cmd
5
0 0 1 0 1
6
0 0 0 0 0 1
0

Output

cmd
Mary won 3 times and John won 2 times
Mary won 5 times and John won 1 times

### #5 Code Example with Python Programming

```Code - Python Programming```

``````
while True:
n = int(input())
if n == 0: break
lis = str(input())
m = lis.count('0')
j = n - m
print('Mary won {} times and John won {} times'.format(m, j))

``````
Copy The Code &

Input

cmd
5
0 0 1 0 1
6
0 0 0 0 0 1
0

Output

cmd
Mary won 3 times and John won 2 times
Mary won 5 times and John won 1 times