## Algorithm

Problem Name:  beecrowd | 1066

# Even, Odd, Positive and Negative

Adapted by Neilor Tonin, URI Brazil

Timelimit: 1

Make a program that reads five integer values. Count how many   of these values are even, odd, positive and negative. Print these information like following example.

## Input

The input will be 5 integer values.

## Output

Print a message like the following example with all letters in lowercase, indicating how many of these values ​​are even, odd, positive and negative.

 Input Sample Output Sample -5 0 -3 -4 12 3 valor(es) par(es) 2 valor(es) impar(es) 1 valor(es) positivo(s) 3 valor(es) negativo(s)

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````
#include <stdio.h>

int main()
{
int n, i;
int pos = 0, neg = 0, par = 0, im = 0;

for(i = 0; i  <  5; ++i)
{
scanf("%d", &n);
if(n > 0) {
pos++;
} else {
if(n != 0){
neg++;
}
}

if(n % 2 == 0) {
par++;
} else {
im++;
}
}

printf("%d valor(es) par(es)n", par);
printf("%d valor(es) impar(es)n", im);
printf("%d valor(es) positivo(s)n", pos);
printf("%d valor(es) negativo(s)n", neg);

return 0;
}
``````
Copy The Code &

Input

cmd
-5 0 -3 -4 12

Output

cmd
3 valor(es) par(es) 2 valor(es) impar(es) 1 valor(es) positivo(s) 3 valor(es) negativo(s)

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include <iostream>

using namespace std;

int main()
{
int n;
int pos = 0, neg = 0, par = 0, im = 0;

for(int i = 0; i  <  5; ++i)
{
cin >> n;
if(n > 0) {
pos++;
} else {
if(n != 0) {
neg++;
}
}

if(n % 2 == 0) {
par++;
} else {
im++;
}
}

cout << par << " valor(es) par(es)" << endl;
cout << im << " valor(es) impar(es)" << endl;
cout << pos << " valor(es) positivo(s)" << endl;
cout << neg << " valor(es) negativo(s)" << endl;

return 0;
}
``````
Copy The Code &

Input

cmd
-5 0 -3 -4 12

Output

cmd
3 valor(es) par(es) 2 valor(es) impar(es) 1 valor(es) positivo(s) 3 valor(es) negativo(s)

### #3 Code Example with Java Programming

```Code - Java Programming```

``````
import java.util.Scanner;

public class Main {

public static void main(String[] args) {

int X, even = 0,odd = 0,positive = 0,negative = 0;
Scanner input =new Scanner(System.in);
for (int i = 1; i  < = 5; i++) {
X = input.nextInt();
if (X % 2 == 0) {
even += 1;
}
if (X % 2 != 0) {
odd += 1;
}
if (X > 0) {
positive += 1;
}
if (X  <  0) {
negative += 1;
}

}
System.out.print(even+" valor(es) par(es)n");
System.out.print(odd+" valor(es) impar(es)n");
System.out.print(positive+" valor(es) positivo(s)n");
System.out.print(negative+" valor(es) negativo(s)n");

}

}
``````
Copy The Code &

Input

cmd
-5 0 -3 -4 12

Output

cmd
3 valor(es) par(es) 2 valor(es) impar(es) 1 valor(es) positivo(s) 3 valor(es) negativo(s)

### #4 Code Example with Python Programming

```Code - Python Programming```

``````
even=0
odd=0
positive=0
negative=0
for i in range(5):
n = float(input())
if(n % 2 == 0):
even = even+1
else:
odd =odd+1
if (n > 0):
positive =positive+1
elif (n < 0):
negative =negative+1
print(f"{even} valor(es) par(es)")
print(f"{odd} valor(es) impar(es)")
print(f"{positive} valor(es) positivo(s)")
print(f"{negative} valor(es) negativo(s)">
``````
Copy The Code &

Input

cmd
-5 0 -3 -4 12

Output

cmd
3 valor(es) par(es) 2 valor(es) impar(es) 1 valor(es) positivo(s) 3 valor(es) negativo(s)