## Algorithm

Problem Name: 2 AD-HOC - beecrowd | 2569

# The 7 x 1 Witch

By Ricardo Martins, IFSULDEMINAS Brazil

Timelimit: 1

Dona Clotilde is a very nice lady who lives in a village, in house which number is 71. It's not known why, but she had a reputation for being a witch. Clotilde was eager to watch a football game. One day, she bought a liquid to clean silver. With this, she won a coupon that gave her a number to compete for a ticket to the 2014 World Cup semifinal at Mineirão, the game between Germany and Brazil. The raffle happened and she won the ticket. Clotilde went to the game, Brazil lost 7 x 1, and everyone in the village thought that Brazil had lost that way because of her, poor thing! Her hacking nephew, San Tanaz, taking her aunt's pains, decided to create a computer virus that interfered with mathematical calculations, so that anything involving number 7 in the accounts would become 0.

For example:

3 + 4 = 0

33 + 44 = 0

17 + 11 = 21

8 x 9 = 2

12 x 7 = 0

8 + 9 = 10

## Input

Composed of a single line with two integers a and b (0 < a, b < 10000), separated by a sum or multiplication operator.

## Output

An integer corresponding to the result of the account, after the virus.

 Input Samples Output Samples 3 + 4 0

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````
#include <stdio.h>
#include <string.h>

void retiraZero(const char *, char *);
long int StrToInt(char *str);
void IntToStr(unsigned short, char *);

int main (void)
{

char operacao;

scanf("%s %c %s", operandoA, &operacao, operandoB);

retiraZero(operandoA, operandoASem7);
retiraZero(operandoB, operandoBSem7);

if (operacao == '+')
else if (operacao == 'x')

}

void retiraZero(const char *operando, char *operandoSem7)
{

unsigned short i = 0;
unsigned short j = 0;

while (operando[i])
{

if (operando[i] == '7')
operandoSem7[j++] = '0';
else
operandoSem7[j++] = operando[i];

i++;
}

operandoSem7[j] = '\0';

}

long int StrToInt(char *str)
{

long int i, multiplicador = 1, numero = 0;

for(i = strlen(str) - 1; i >= 0; i--, multiplicador *= 10)
numero +=  (str[i] - 48) * multiplicador;

return numero;
}
``````
Copy The Code &

Input

cmd
3 + 4

### #2 Code Example with Python Programming

```Code - Python Programming```

``````
s=input().split()
n1=str(s[0].replace('7','0'))
op=s[1]
n2=str(s[2].replace('7','0'))
res=str(int(n1)+int(n2)) if op=='+' else str(int(n1)*int(n2))
res=int(res.replace('7','0'))
print(res)
``````
Copy The Code &

Input

cmd
3 + 4