Algorithm
Problem Name: beecrowd | 2003
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/2003
Sunday Morning
By Thalyson Nepomuceno, UECE 
Brazil
Timelimit: 1
Sunday is market day. Early in the morning many people move to the Parangaba square where happens a fair, known to be the largest in the city. At the fair the Parangaba you can find everything.
Every Sunday, Bino make purchases at the fair. He always mark with his friend Cino, they met at the bus terminal of Parangaba at 8 am to go together to buy at the fair. But often Bino wake up too late and is late for the meeting with his friend.
Knowing that Bino takes 30-60 minutes to reach the terminal. Tell the maximum delay Bino.
Input
The input consists of multiple test cases. Each case contains a single line containing a time H (5:00 ≤ H ≤ 9:00) that Bino woken up. The input ends with the final file (EOF).
Output
For each test case, print "Atraso maximo: X" (without quotes), X indicates the maximum delay (in minutes) of Bino in the encounter with Cino.
| Input Sample | Output Sample |
|
7:10 |
Atraso maximo: 10 |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(void) {
int a,b,n;
char aa;
while(scanf("%d %c %d",&a,&aa,&b) != EOF){
printf("Atraso maximo: ");
if(a < 7 || (a == 7 && b == 00))
printf("0\n");
else
printf("%d\n",(a-7)*60 + b>;
}
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b;
char c;
while(cin >> a >> c >> b)
{
int A = a-7;
int B = b;
if(A < 0)cout << "Atraso maximo: 0\n";
else{
printf("Atraso maximo: %d\n",(A*60)+b>;
}
}
return 0;
}
Input
#3 Code Example with Javascript Programming
Code -
Javascript Programming
const { createReadStream } = require("fs")
const { createInterface } = require("readline")
//// READING FILE | STREAMS ////
class LineReader {
/**
* @param {import("fs").PathLike} path
* @param {BufferEncoding} encoding
* @return {import("readline").ReadLine}
*/
static createReadLineInterface(path, encoding = "utf8") {
const readStreamOptions = {
encoding: encoding,
flags: "r",
emitClose: true,
autoClose: true
}
return createInterface({
input: createReadStream(path, readStreamOptions),
crlfDelay: Infinity,
terminal: false
})
}
/**
* @param {import("fs").PathLike} path
* @param {BufferEncoding} encoding
*/
static create(path, encoding) {
const RLI = LineReader.createReadLineInterface(path, encoding)
let EOF = false
const nextLineGenerator = (async function* () {
for await (const line of RLI)
yield line
})()
RLI.once("close", () => { EOF = true })
return {
hasNextLine: () => !EOF,
nextLine: async (/** @type {unknown} */ fn) => {
const { value } = (await nextLineGenerator.next())
return (typeof fn === "function") ? fn(value) : value
},
close: () => RLI.close()
}
}
}
const calcMaximumDelayTime = (hours, minutes) => (hours >= 7) ? ((hours - 7) * 60) + minutes : 0
async function main() {
const PATH = "/dev/stdin"
const ENCODING = "utf8"
const lineReader = LineReader.create(PATH, ENCODING)
const helper = (line = "") => line.split(":", 2).map(value => Number.parseInt(value, 10))
const nextLine = lineReader.nextLine.bind(null, helper)
const output = []
while (lineReader.hasNextLine()) {
const [hour, min] = await nextLine()
if (Number.isNaN(hour) || Number.isNaN(min)) break // EOF
output.push(`Atraso maximo: ${calcMaximumDelayTime(hour, min)}`)
}
if (lineReader.hasNextLine())
lineReader.close()
console.log(output.join("\n"))
}
main()
Input
#4 Code Example with Python Programming
Code -
Python Programming
while True:
try:
hora = input().split(':')
n = int(hora[0])*60 + int(hora[1]) - 420
if n < 0:
n = 0
print('Atraso maximo: %d' % n)
except EOFError:
break
Input
Output