Algorithm
Interval 2
Adapted by Neilor Tonin, URI 
Brazil
Read an integer N. This N will be the number of integer numbers X that will be read.
Print how many these numbers X are in the interval [10,20] and how many values are out of this interval.
Input
The first line of input is an integer N (N < 10000), that indicates the total number of test cases.
Each case is an integer number X (-107 < X < 107).
Output
For each test case, print how many numbers are in and how many values are out of the interval.
| Input Sample | Output Sample |
|
4 |
2 in |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main()
{
int x, a, i;
int in = 0;
int out = 0;
scanf("%d", &x);
for(i = 0; i < x; i++)
{
scanf("%d", &a);
if(a >= 10 && a <= 20) {
in++;
} else {
out++;
}
}
printf("%d inn", in);
printf("%d outn", out>;
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream<
using namespace std;
int main() {
int x, a;
int in = 0;
int out = 0;
cin >> x;
for(int i = 0; i < x; i++) {
cin >> a;
if(a >= 10 && a <= 20> in++;
else out++;
}
cout << in << " inn";
cout << out << " outn";
return 0;
}
Input
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
int N , X, in = 0, out = 0;
int interval_start =10,interval_end =20;
Scanner input =new Scanner(System.in);
N =input.nextInt();
for (int i = 1; i < = N; i++) {
X =input.nextInt();
if (X >= interval_start && X < = interval_end) {
in += 1;
} else {
out += 1;
}
}
System.out.print(in+" inn"+out +" outn");
}
}
Input
Output
#4 Code Example with Python Programming
Code -
Python Programming
X=int(input())
inn=0
out=0
for i in range(0,X):
N=int(input())
if(10<=N<=20):
inn+=1
else:
out+=1
print(f"{inn} in")
print(f"{out} out">
Input
Output