## Algorithm

Problem Name: beecrowd | 2708

# Tourists in the Huacachina Park

By André Marcos Silva Brazil

Timelimit: 1

The municipal tourism agency of the city of Ica in Peru has set up a checkpoint for adventure jeeps that ascend to the dunes of Hucachina Park. As during the day, there are several off-roads that go up and down the national park, and tourists do not always use the same transportation for the round trip, the city hall needed to have better control and security over the flow of visitors in the park. Develop a program that receives as input if a jeep is entering or returning from the park and the amount of tourists this vehicle is transporting. At the end of the shift, the program must indicate how many vehicles and tourists are still missing from the adventure.

## Input

The program must receive successive input pairs. Each pair should indicate the jeep's movement and the amount of tourists it is carrying. The first entry should be "SALIDA" or "VUELTA". "SALIDA" should indicate that the jeep is leaving the center and entering the park; and "VUELTA" that the Jeep is returning from the ride. Immediately following, the program receives an integer T (where, 0 <= T <=20) indicating the amount of tourists being transported by the jeep. The string "ABEND" should be the end-of-processing indicator.

## Output

As a goal the program must present two exits, one in each line: the amount of tourists and the amount of jeeps that still need to return from the park.

 Input Samples Output Samples SALIDA 10 SALIDA 12 SALIDA 10 VUELTA 20 ABEND 12 2

 SALIDA 15 SALIDA 20 VUELTA 15 VUELTA 15 SALIDA 0 VUELTA 0 ABEND 5 0

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````
#include <stdio.h>
#include <string.h>

struct s
{
char str[10];
int n;
};

int main(void)

{
int i, j, sum, in=0, out=0, pin=0, pout=0;
struct s x;

while (1)
{
scanf("%s", x.str);

if (strcmp(x.str, "ABEND")==0)
break;

scanf("%i", &x.n);

if (strcmp(x.str, "SALIDA")==0)
{
++in;
pin+=x.n;
}

else if (strcmp(x.str, "VUELTA")==0)
{
++out;
pout+=x.n;
}
}

printf("%i\n%i\n", pin-pout, in-out);

return 0;
}

``````
Copy The Code &

Input

cmd
SALIDA 10 SALIDA 12 SALIDA 10 VUELTA 20 ABEND

Output

cmd
12 2

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include <iostream>
#include<stdio.h>
#include<math.h>
#include<algorithm>
#include<stack>
#include<queue>
#include<set>
#include<map>
#include<vector>
#include<math.h>
#include<string>
#include<list>

using namespace std;

#define ll long long
#define input scanf
#define output printf
#define Loop while
#define echo cout
#define ret return
#define MAX 999999999999999999
#define MIN 0
#define PI 3.1415

bool isPrime(int x);
void sieve();
string toBinary(int n);
bool findingSubString(string a,string b);
vector<int> a(32);
int main(int argc, char** argv) {

//freopen("c.txt","w",stdout);
string str;
int a;
int sum=0;
int out=0;
while(cin >> str&&str[0]!='A')
{
cin >> a;
if(str[0]=='S')
{
out++;
sum+=a;
}
else
{
out--;
sum-=a;
}
}
printf("%d\n%d\n",sum,out);
ret 0;
}
``````
Copy The Code &

Input

cmd
SALIDA 10 SALIDA 12 SALIDA 10 VUELTA 20 ABEND

Output

cmd
12 2

### #3 Code Example with Python Programming

```Code - Python Programming```

``````
turistas = 0
jipes = 0
while True:
break
jipes += 1
else:
jipes -= 1

print(turistas)
print(jipes)
``````
Copy The Code &

Input

cmd
SALIDA 10 SALIDA 12 SALIDA 10 VUELTA 20 ABEND

Output

cmd
12 2

### #4 Code Example with Javascript Programming

```Code - Javascript Programming```

``````
const { readFileSync } = require("node:fs")

outer:
for (let index = 0, s = 0, j = 0; index  <  input.length; index += 2) {
switch (input[index]) {
case "SALIDA":
s += Number.parseInt(input[index + 1], 10)
j++
break
case "VUELTA":
s -= Number.parseInt(input[index + 1], 10)
j--
break
case "ABEND":
console.log("%d\n%d", s, j)
break outer
}
}

``````
Copy The Code &

Input

cmd
SALIDA 10 SALIDA 12 SALIDA 10 VUELTA 20 ABEND

Output

cmd
12 2