## Algorithm

Problem Name: beecrowd | 1960

# Roman Numerals for Page Numbers

By M.C. Pinto, UNILA Brazil

Timelimit: 1

The ECI (Editio Chronica Incredibilis or Amazing Chronicles Editors) is very traditional when numbering the pages of its books. It always uses the Roman numerals for that. And its books never have more than 999 pages. When necessary, the books are split into volumes.

You must write a program that, given an arabic number, show its equivalent in roman numerals.

Remember that I stands for 1, V for 5, X for 10, L for 50, C for 100, D for 500 and M stands for 1000.

## Input

The input is a positive integer number N (0 < N < 1000).

## Output

The output is the number N written as Roman numerals in a single line. Always use uppercase letters.

 Input Samples Output Samples 666 DCLXVI

 83 LXXXIII

 999 CMXCIX

## Code Examples

### #1 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include <bits/stdc++.h>
using namespace std;

int main()
{
int n , temp;
string s;

cin >> s;
int len = s.length();
if(len==3)
{
if(s[0]=='1') printf("C");
else if(s[0]=='2') printf("CC");
else if(s[0]=='3') printf("CCC");
else if(s[0]=='4') printf("CD");
else if(s[0]=='5') printf("D");
else if(s[0]=='6') printf("DC");
else if(s[0]=='7') printf("DCC");
else if(s[0]=='8') printf("DCCC");
else if(s[0]=='9') printf("CM");
if(s[1]=='1') printf("X");
else if(s[1]=='2') printf("XX");
else if(s[1]=='3') printf("XXX");
else if(s[1]=='4') printf("XL");
else if(s[1]=='5') printf("L");
else if(s[1]=='6') printf("LX");
else if(s[1]=='7') printf("LXX");
else if(s[1]=='8') printf("LXXX");
else if(s[1]=='9') printf("XC");
if(s[2]=='1') printf("I");
else if(s[2]=='2') printf("II");
else if(s[2]=='3') printf("III");
else if(s[2]=='4') printf("IV");
else if(s[2]=='5') printf("V");
else if(s[2]=='6') printf("VI");
else if(s[2]=='7') printf("VII");
else if(s[2]=='8') printf("VIII");
else if(s[2]=='9') printf("IX");
}
else if(len==2)
{
if(s[0]=='1') printf("X");
else if(s[0]=='2') printf("XX");
else if(s[0]=='3') printf("XXX");
else if(s[0]=='4') printf("XL");
else if(s[0]=='5') printf("L");
else if(s[0]=='6') printf("LX");
else if(s[0]=='7') printf("LXX");
else if(s[0]=='8') printf("LXXX");
else if(s[0]=='9') printf("XC");
if(s[1]=='1') printf("I");
else if(s[1]=='2') printf("II");
else if(s[1]=='3') printf("III");
else if(s[1]=='4') printf("IV");
else if(s[1]=='5') printf("V");
else if(s[1]=='6') printf("VI");
else if(s[1]=='7') printf("VII");
else if(s[1]=='8') printf("VIII");
else if(s[1]=='9') printf("Is");
}
else if(len==1)
{
if(s[0]=='1') printf("I");
else if(s[0]=='2') printf("II");
else if(s[0]=='3') printf("III");
else if(s[0]=='4') printf("IV");
else if(s[0]=='5') printf("V");
else if(s[0]=='6') printf("VI");
else if(s[0]=='7') printf("VII");
else if(s[0]=='8') printf("VIII");
else if(s[0]=='9') printf("IX");
}
cout << endl;

return 0;
}
``````
Copy The Code &

Input

cmd
666

Output

cmd
DCLXVI

### #2 Code Example with Javascript Programming

```Code - Javascript Programming```

``````
var lines = input.split('\n');
let numero = parseInt(lines.shift());

const arabicos = [900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1];
const romanos = ['CM', 'D', 'CD', 'C', 'XC', 'L', 'XL', 'X', 'IX', 'V', 'IV', 'I'];

let i = 0;

while (numero > 0) {
if (numero >= arabicos[i]) {
numero -= arabicos[i];
} else {
i++;
}
}

``````
Copy The Code &

Input

cmd
666

Output

cmd
DCLXVI