Algorithm
Problem Name: beecrowd | 2727
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/2727 
Secret Code
By Juliane Alves, UFRGS  Brazil
 Brazil
Timelimit: 1
Joana likes to play pretending to be a secret agent with her friends Bruna, Jaqueline and Laura. Joana and Bruna have created a secret code to communicate without their enemies discovering their plans. The secret code works as follows:
- The letter 'a' is represented by a single dot '.'
- The letter 'b' is represented by two dots '..'
- The letter 'c' is represented by three dots '...'
- The other letters follow the previous logic, however each set of points is separated by a space and always with a set of more points, as in the example below:
. → a
 .. → b
... → c
. . → d
.. .. → e
 ... ... → f
. . . → g
 .. .. .. → h
 ... ... ... → i
Your goal is to create a program that decipher the secret messages and help Jaqueline and Laura find out what Joana and Bruna are planning.
Input
The input contains several test cases. The first line of each test should contain an integer (N ≤ 50), which represents the number of letters to be deciphered and the next N lines contain the code for each letter.
Output
A string represented by the letter of the alphabet corresponding to the input code. Each string must be separated from the other by a new line.
| Input Sample | Output Sample | 
| 2 | o | 
Code Examples
#1 Code Example with C++ Programming
Code -
                                                        C++ Programming
#include <iostream>
#include <string>
#include <vector>
#include <cstdio>
using namespace std;
int main()
{
    int n;
    string str;
    while (cin >> n)
    {
        getline(cin, str);
        while (n--)
        {
            getline(cin, str);
            bool flag=true;
            int s=0, d=0, x;
            char c;
            for (int j = 0; j  <  str.size(); ++j)
            {
                if (str[j]==' ')
                {
                    s++;
                    flag=false;
                }
                if (flag)
                    d++;
            }
            x=(3*s)+(d-1);
            c=x+'a';
            printf("%c\n", c);
        }
    }
    return 0;
}
Input
Output
#2 Code Example with Java Programming
Code -
                                                        Java Programming
import java.util.Scanner;
public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		
		while(sc.hasNext()) {
			int n = Integer.parseInt(sc.nextLine());
			String[] cod = new String[n];
			for (int x = 0 ; x  <  n ; x++)
				cod[x] = sc.nextLine();
			for (int x = 0 ; x  <  n ; x++) {
				if(cod[x].equals(".")) System.out.println("a");
				if(cod[x].equals("..")) System.out.println("b");
				if(cod[x].equals("...")) System.out.println("c");
				if(cod[x].equals(". .")) System.out.println("d");
				if(cod[x].equals(".. ..")) System.out.println("e");
				if(cod[x].equals("... ...")) System.out.println("f");
				if(cod[x].equals(". . .")) System.out.println("g");
				if(cod[x].equals(".. .. ..")) System.out.println("h");
				if(cod[x].equals("... ... ...")) System.out.println("i");
				if(cod[x].equals(". . . .")) System.out.println("j");
				if(cod[x].equals(".. .. .. ..")) System.out.println("k");
				if(cod[x].equals("... ... ... ...")) System.out.println("l");
				if(cod[x].equals(". . . . .")) System.out.println("m");
				if(cod[x].equals(".. .. .. .. ..")) System.out.println("n");
				if(cod[x].equals("... ... ... ... ...")) System.out.println("o");
				if(cod[x].equals(". . . . . .")) System.out.println("p");
				if(cod[x].equals(".. .. .. .. .. ..")) System.out.println("q");
				if(cod[x].equals("... ... ... ... ... ...")) System.out.println("r");
				if(cod[x].equals(". . . . . . .")) System.out.println("s");
				if(cod[x].equals(".. .. .. .. .. .. ..")) System.out.println("t");
				if(cod[x].equals("... ... ... ... ... ... ...")) System.out.println("u");
				if(cod[x].equals(". . . . . . . .")) System.out.println("v");
				if(cod[x].equals(".. .. .. .. .. .. .. ..")) System.out.println("w");
				if(cod[x].equals("... ... ... ... ... ... ... ...")) System.out.println("x");
				if(cod[x].equals(". . . . . . . . .")) System.out.println("y");
				if(cod[x].equals(".. .. .. .. .. .. .. .. ..")) System.out.println("z");
			}
		}
		sc.close();
	}
}
Input
Output
#3 Code Example with Javascript Programming
Code -
                                                        Javascript Programming
const { readFileSync } = require("fs")
const input = readFileSync("/dev/stdin", "utf8").split("\n")
function getCharFromSequence(sequence = "") {
	const BASE = 96
	const splittedSeq = sequence.split(" ")
	const len = splittedSeq.length - 1
	const [point] = splittedSeq
	const index = BASE + point.length + len * 3
	return String.fromCharCode(index)
}
function main() {
	const responses = []
	while (input.length > 0) {
		const rows = Number.parseInt(input.shift())
		if (isNaN(rows)) break // EOFile Condition Verification
		const pointsSequences = input.splice(0, rows).map(getCharFromSequence)
		responses.push(...pointsSequences)
	}
	console.log(responses.join("\n"))
}
main()
Input
Output
#4 Code Example with Python Programming
Code -
                                                        Python Programming
while True:
    try:
        alf = 'abcdefghijklmnopqrstuvwxyz'
        n = int(input())
        saida = ''
        while n > 0:
            l = input().split()
            pos = len(l[0]) + 3*(len(l)-1)
            saida += alf[pos-1]
            n -= 1
        for n in saida:
            print(n)
    except EOFError:
        break
Input
Output
