## Algorithm

Problem Name: beecrowd | 1149

# Summing Consecutive Integers

Adapted by Neilor Tonin, URI Brazil

Timelimit: 1

Write an algorithm to read a value A and a value N. Print the sum of N numbers from A (inclusive). While N is negative or ZERO, a new N (only N) must be read. All input values are in the same line.

## Input

The input contains only integer values, ​​can be positive or negative.

## Output

The output contains only an integer value.

 Input Sample Output Sample 3 2 7

 3 -1 0 -2 2 7

## Code Examples

### #1 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include <bits/stdc++.h>

using namespace std;

int main(){
int a, n;
cin >> a;
cin >> n;
while(n  < = 0){ cin >> n;}
int sum = 0;
for (int i = 0; i  <  n; i++){
sum += i + a;
}
cout << sum << endl;
return 0;
}
``````
Copy The Code &

Input

cmd
3 2

Output

cmd
7

### #2 Code Example with Java Programming

```Code - Java Programming```

``````
import java.io.IOException;
import java.util.Scanner;

public class Main{
public static void main(String[] args) throws IOException{
Scanner input = new Scanner(System.in);
int a = input.nextInt();
int n = input.nextInt();
while(n  < = 0){ n = input.nextInt();}
int sum = 0;
for (int i = 0; i  <  n; i++){
sum += i + a;
}
System.out.println(sum);
}
}
``````
Copy The Code &

Input

cmd
3 2

Output

cmd
7

### #3 Code Example with Javascript Programming

```Code - Javascript Programming```

``````
// var lines = input.split('\n');
var sep = [' ', '\n'];
// console.log(separators.join('|'));
var line = input.split(new RegExp(sep.join('|'), 'g'));

var a = parseInt(line.shift());
var n = parseInt(line.shift());

while(n  < = 0){ n = parseInt(line.shift());}

var sum = 0;
for (var i = 0; i  <  n; i++){
sum += i + a;
}
console.log(sum);
``````
Copy The Code &

Input

cmd
3 2

Output

cmd
7

### #4 Code Example with Python Programming

```Code - Python Programming```

``````
list_num = list(map(int, input().split(" ")))
a = list_num[0]
n = 0
for i in range(1, len(list_num)):
k = list_num[i]
if (k > 0):
n = k
break

sum = 0
for i in range(n):
sum += i + a

print(sum)
``````
Copy The Code &

Input

cmd
3 2

Output

cmd
7